Answer:
26.833 N
Explanation:
The computation of the resaltant of two forces is shown below:
Given that
Force A = 12N
Force B = 24N
Based on the above information
Resultant R is
![=\sqrt{A^2 + B^2 + 2AB \times cos \theta}\\\\=\sqrt{144 + 576 + 2\times 24\times 12\times cos90^{\circ}}\\\\=\sqrt{144+576+576\times 0}\\\\=\sqrt{720}](https://tex.z-dn.net/?f=%3D%5Csqrt%7BA%5E2%20%2B%20B%5E2%20%2B%202AB%20%5Ctimes%20cos%20%5Ctheta%7D%5C%5C%5C%5C%3D%5Csqrt%7B144%20%2B%20576%20%2B%202%5Ctimes%2024%5Ctimes%2012%5Ctimes%20cos90%5E%7B%5Ccirc%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B144%2B576%2B576%5Ctimes%200%7D%5C%5C%5C%5C%3D%5Csqrt%7B720%7D)
=26.833 N
Answer:
Power = 130 watt
Explanation:
Power is described as the ability to do work, it is also defined as the amount of work in Joules done in a given time in seconds. Mathematically, it is represented as:
![power = \frac{work (J)}{Time (s)}](https://tex.z-dn.net/?f=power%20%3D%20%5Cfrac%7Bwork%20%28J%29%7D%7BTime%20%28s%29%7D)
In this example, power is calculated as follows:
Work = 39000 J
Time = 5 minutes
converting the time from minutes to seconds:
1 minute = 60 seconds
∴ 5 minutes = 60 × 5 = 300 seconds
![\therefore power = \frac{39000}{300} \\power = 130 watt](https://tex.z-dn.net/?f=%5Ctherefore%20power%20%3D%20%5Cfrac%7B39000%7D%7B300%7D%20%5C%5Cpower%20%3D%20130%20watt)
N:B the unit for power can also be represented as Joules/seconds or J/s or JS⁻¹
Answer:
The heater power required is 2400 W. The power in the heater can be calculated as the product of the voltage line and the steady current:
![P=120 V * 20 A = 2400 VA = 2400 W](https://tex.z-dn.net/?f=P%3D120%20V%20%2A%2020%20A%20%3D%202400%20VA%20%3D%202400%20W)
Explanation:
Answer:
B. Kinetic energy.............