Answer: heat
Insulation Traps Heat. Keeping the cold air out
Explanation:
The attractive force between all matter in the universe is gravity.
Answer:
<em>The magnitude of the force is 10 N</em>
Explanation:
<u>Coulomb's Law</u>
The electrostatic force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.
Written as a formula:
![\displaystyle F=k\frac{q_1q_2}{d^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20F%3Dk%5Cfrac%7Bq_1q_2%7D%7Bd%5E2%7D)
Where:
![k=9\cdot 10^9\ N.m^2/c^2](https://tex.z-dn.net/?f=k%3D9%5Ccdot%2010%5E9%5C%20N.m%5E2%2Fc%5E2)
q1, q2 = the objects' charge
d= The distance between the objects
We have two identical charges of q1=q2=1 c separated by d=30000 m, thus the magnitude of the force is:
![\displaystyle F=9\cdot 10^9\frac{1*1}{30000^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20F%3D9%5Ccdot%2010%5E9%5Cfrac%7B1%2A1%7D%7B30000%5E2%7D)
![\displaystyle F=9\cdot 10^9\frac{1*1}{30000^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20F%3D9%5Ccdot%2010%5E9%5Cfrac%7B1%2A1%7D%7B30000%5E2%7D)
F = 10 N
The magnitude of the force is 10 N
Answer:
The work done to get you safely away from the test is 2.47 X 10⁴ J.
Explanation:
Given;
length of the rope, L = 70 ft
mass per unit length of the rope, μ = 2 lb/ft
your mass, W = 120 lbs
mass of the 70 ft rope = 2 lb/ft x 70 ft
= 140 lbs.
Total mass to be pulled to the helicopter, M = 120 lbs + 140 lbs
= 260 lbs
The work done is calculated from work-energy theorem as follows;
W = Mgh
where;
g is acceleration due gravity = 32.17 ft/s²
h is height the total mass is raised = length of the rope = 70 ft
W = 260 Lb x 32.17 ft/s² x 70 ft
W = 585494 lb.ft²/s²
1 lb.ft²/s² = 0.0421 J
W = 585494 lb.ft²/s² = 2.47 X 10⁴ J.
Therefore, the work done to get you safely away from the test is 2.47 X 10⁴ J.