A student walks a distance of 3 km in 20 minutes calculate his average speed

A park ranger wants to shoot a monkey hanging from a branch of a tree with a tranquilizing dart. The ranger aims directly at the

puteri [66]

Answer:

Yes it will hit the monkey

Explanation:

Here when park ranger aim the position of monkey and then shoot towards it then in this position the velocity of the dart has two components

$v_x = vcos\theta$

$v_y = vsin\theta$

Now when the dart reached the same horizontal distance as that the position of monkey then time taken by it

$t = \frac{x}{v cos\theta}$

now in the same time the height of the dart is given as

$y = (vsin\theta) t - \frac{1}{2}gt^2$

$y = (vsin\theta)(\frac{x}{vcos\theta}) - \frac{1}{2}g(\frac{x}{vcos\theta})^2$

$y = x tan\theta - \frac{1}{2}gt^2$

here let say monkey is at height H initially then

$H = x tan\theta$

$y = H - \frac{1}{2}gt^2$

this above equation also shows the position of monkey after t time of drop

so here dart will hit the monkey

8 0

3 years ago

Read 2 more answers

An electron moves 4.5 m in the direction of an electric field of strength of 325N/C. Determine the change in electrical potentia

makkiz [27]

The change in electrical potential energy of the electron is given by:
$\Delta U = e \Delta V$
where
e is the electron charge
$\Delta V$ is the potential difference between the initial and final point of the electron.

The electron moves by a distance d=4.5 m in the electric field of intensity $E=325 N/C$ , so the potential difference between the initial and final location of the electron is
$\Delta V= -E d= -(325 N/C)(4.5 m)=-1462.5 V$
where the negative sign is due to the fact that the electron is moving in the direction of the electric field, so it is moving from a point at higher potential to a point of lower potential, so the $\Delta V$ must be negative.

Therefore, the change in electrical potential energy of the electron is
$\Delta U= e \Delta V=(-1.6 \cdot 10^{-19} C)(-1462.5 V)=2.34 \cdot 10^{-16} J$

8 0

4 years ago

Which resistors in the circuit must have the same amount of charge passing through each second?

Nutka1998 [239]

Answer:

Option B) C and D

Explanation:

The amount of charge passing through a resistor each second corresponds to the definition of current, so the problem is asking "which resistors have the same amount of current".

Let's keep in mind that:

- When two resistors are in series (=they are connected into the same branch of the circuit), the current flowing through each resistor is the same

- When two resistors are in parallel (=they are connected into different branches), the potential difference across each resistor is the same

Looking at the previous definitions, we have to find the two resistors in the circuit that are connected in series. We see that resistors C and D are in the same branch, so they are in series: therefore, the current flowing through resistor C and D is the same.

5 0

3 years ago

Amy, standing near a straight road, records the sound of the horn of a car traveling at a constant speed. The recorded frequency

myrzilka [38]

(1) The speed in trial U is less than that in Q.

(2) The speed in trial T is greater than that in other trials.

(3) The distance of Amy from the path in R is equal to distance in S.

(4) The speed in trial U is less than that in other trials.

(5) When the car is far away, the average of the frequencies moving in and out is equal to the frequency at rest.

(6) The speed in trial R is equal to that in S.

(7) The speed of the car in trial T is 58.6 m/s.

<h3>Speed of wave</h3>

The speed of a wave is directly proportional to its frequency and wavelength.

v = fλ

where;

v is speed of the wave
f is frequency of the wave
λ is wave length

The speed in trial U is less than that in Q, due to greater frequency observed in trial Q.

The speed in trial T is greater than that in other trials, due to greater frequency observed in trial T.

The distance of Amy from the path in R is equal to distance in S.

The speed in trial U is less than that in other trials.

<h3>Average of the frequencies when the car is far away</h3>

f(avg) = (1,055 + 1,020 + 986 + 985 + 940 + 862 + 830 + 828 + 808 + 730)/10

= 904.3 ≈ 900 Hz

When the car is far away, the average of the frequencies moving in and out is equal to the frequency at rest.

The speed in trial R is equal to that in S.

<h3>Speed of the car in trial T</h3>

f = f₀(v / v - vs)

where;

f is frequency of the car at zero position
f₀ is the original frequency
vs is the speed of the car
v is speed of sound

900 = 1055(340 / 340 - vs)

900/1055 = 340/340 - vs

0.853 = 340/340 - vs

340 - vs = 340/0.853

340 - vs = 398.6

vs = 398.6 - 340

vs = 58.6 m/s

Learn more about speed of wave here: brainly.com/question/2142871

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6 0

2 years ago

25.16 what is the reaction product of acetic acid and ethylamine at room temperature?

Ne4ueva [31]

The ammonium salt of acetic acid is the reaction product of acetic acid and ethylamine at room temperature

<h3 /><h3>What is acetic acid ?</h3>

Acetic acid is a monofunctional carboxylic acid containing two carbon atoms. It acts as a protein solvent, food acidity regulator, antibacterial food preservative. It is a conjugate acid of an acetate.

Acetic acid is used in the production of acetic anhydride, cellulose acetate, vinyl acetate monomer, acetic ester, chloroacetic acid, plastics, dyes, insecticides, photographic chemicals, and rubber. Other commercial uses include the production of vitamins, antibiotics, hormones, organic chemicals, and as a food additive. Typical concentrations of acetic acid found naturally in foods are 700 to 1200 milligrams/kg (mg/kg) in wine, up to 860 mg/kg in aged cheeses, and 2.8 mg/kg in aged cheeses. fresh orange juice.

learn more about acetic acid, visit;

brainly.com/question/16970860

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7 0

1 year ago