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4 years ago

Please help! I only need the equations not the graphing

Mathematics

1 answer:

Anvisha [2.4K]4 years ago

6 0

Answer:

x + y ≥ 4

8x + 10y ≤ 70

Step-by-step explanation:

1. State the variables

According to the graph, "Number of green towels" is on the x-axis, and "Number of blue towels" is on the y-axis, so:

let x be the number of green towels.

let y be the number of blue towels

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2. <u>Write an equation for the total number of towels</u>.

The sum of number of green towels and the number of blue towels is the total number of towels.

x + y ≥ 4

"She wants to buy at least 4 towels" means she needs 4 or more. Use the ≥ symbol instead of > (which would mean more than 4 towels, not only 4).

3. <u>Write an equation for the money</u> she will spend.

Multiply each variable by the cost of the towel colour. Add them together. Equate the total as 70 because she is only willing to spend 70.

8x + 10y ≤ 70

"She does not want to spend more than $70" means she is willing to spend 70, but no more. This is why we use ≤ and not < (which would mean she would not spend 70, only less than 70).

The equations are x + y ≥ 4 and 8x + 10y ≤ 70.

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maw [93]

Answer:

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2. x > -2

3. 2.86 inches

^The formula for the circumference of a circle is C=2∏r, in which r=radius. To find the radius, then, we insert 18 in for the circumference. So 18=2∏r. Solving for r gives 9/∏, or approximately 2.86 inches.

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Brainliest?

8 0

3 years ago

An air transport association surveys business travelers to develop quality ratings for transatlantic gateway airports. The maxim

Flura [38]

Answer:

The 95% confidence interval estimate of the population mean rating for Miami is (6.0, 7.5).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the population mean, when the population standard deviation is not provided is:

$CI=\bar x \pm t_{\alpha/2, (n-1)}\cdot \frac{s}{\sqrt{n}}$

The sample selected is of size, <em>n</em> = 50.

The critical value of <em>t</em> for 95% confidence level and (<em>n</em> - 1) = 49 degrees of freedom is:

$t_{\alpha/2, (n-1)}=t_{0.05/2, 49}\approx t_{0.025, 60}=2.000$

*Use a <em>t</em>-table.

Compute the sample mean and sample standard deviation as follows:

$\bar x=\frac{1}{n}\sum X=\frac{1}{50}\times [1+5+6+...+10]=6.76\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}=\sqrt{\frac{1}{49}\times 31.12}=2.552$

Compute the 95% confidence interval estimate of the population mean rating for Miami as follows:

$CI=\bar x \pm t_{\alpha/2, (n-1)}\cdot \frac{s}{\sqrt{n}}$

$=6.76\pm 2.000\times \frac{2.552}{\sqrt{50}}\\\\=6.76\pm 0.722\\\\=(6.038, 7.482)\\\\\approx (6.0, 7.5)$

Thus, the 95% confidence interval estimate of the population mean rating for Miami is (6.0, 7.5).

7 0

3 years ago

Find the solution for the following equation using the algebraic method: 3x^2+10x=8

likoan [24]

The answer should be 0.875.

6 0

3 years ago

1) x+30 = 40

soldier1979 [14.2K]

1)x+30=40

x=40-30

Answer :x=10

2)30-20+2x=10

10+2x=10

2x=0

Answer: x=0

3)3x-10+13=-2x+28

3x+3=-2x+28

3x+2x+3=28

3x+2x=28-3

5x=28-3

5x=25

x=5

4)13x-23-45=-7x+12

13x-68=-7x+12

13x+7x-68=12

13x+7x=12+68

20x=12+68

20x=80

x=4

5)2(x+4)=10x+24

2x+8=10x+24

2x-10x+8=24

2x-10x=24-8

-8x=24-8

-8x=16

x=-2

6)3(x-5)=1-(2x-4)

3x-15=1-(2x-4)

3x-15=1-2x+4

3x-15=5-2x

3x+2x-15=5

3x+2x=5+15

5x=5+15

5x=20

x=4

7)5x-10=15

5x=15+10

5x=25

x=5

8)x+4=x+6

4=6

no solution

PLEASE MARK ME AS BRAINLIEST

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3 years ago

WILL GIVE BRAINLIEST!!!!!!

Dahasolnce [82]

<h2>Greetings!</h2>

Answer:

x = 67.5

Step-by-step explanation:

Because AB and NP lines are parrallel, we can find out the scale factor by dividing size MA by MN.

This works because you find out what the MA size has to be multiplied to to get to MN, which will also work in reverse to find angle MB from MP.

71.5 - 22 = MA = 49.5

71.5 ÷ 49.5 = $\frac{13}{9}$

So to get to line MP length, line MB had to be multiplied by $\frac{13}{9}$ to get 97.5

The reverse of this is dividing 97.5 by $\frac{13}{9}$ :

97.5 ÷ $\frac{9}{13}$ = 67.5

So x = 67.5

<h2>Hope this helps!</h2>

4 0

3 years ago

Please help! I only need the equations not the graphing​

Please help! I only need the equations not the graphing