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34kurt
4 years ago
10

Describe how to transform the graph of g(x)= ln x into the graph of f(x)= ln (3-x) -2.

Mathematics
2 answers:
Alenkasestr [34]4 years ago
5 0

Answer:

A

Step-by-step explanation:

Note the following 3 points with respect to a function given as y = f(x).

1. The function y = f(-x) is a reflection across the y-axis

2. The function y = f(x+a) is a horizontal translation a units left and y = f(x-a) is a horizontal translation a units right

3. the function y = f(x) + a is a vertical translation a units up and y = f(x) - a is a vertical translation a units down

Dissecting the transformed function of  f(x) = ln (3-x) -2   w.r.t   f(x) = ln x, we see:

<em>1. x is replaced with -x, so </em><u><em>reflection across y-axis</em></u>

<em>2. we have a horizontal shift in left side because the argument of ln is (3-x) or (-x+3)</em>

<em>3. We have vertical shift 2 units down because there is a -2 after the functional part of ln(3-x)</em>

<em />

Looking at the choices, A is the right answer.

sveta [45]4 years ago
5 0

Answer:

The actual answer is C

Step-by-step explanation:

I  chose A because of the person above me and got it wrong.

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Given:

\Delta MAT\cong \Delta MHT and m\angle 2=82^\circ.

To find:

Whether m\angle 1=47^\circ is possible or not.

Solution:

We have,

\Delta MAT\cong \Delta MHT

\angle AMT\cong \angle HMT                      (CPCTC)

m\angle 3=m\angle 8              ...(i)

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m\angle 1=m\angle 8              ...(ii)        (Vertically opposite angles)

From (i) and (ii), we get

m\angle 1=m\angle 3              ...(iii)

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m\angle 1+m\angle 2+m\angle 3=180^\circ          (Linear pair)

m\angle 1+82^\circ+m\angle 1=180^\circ             (Using (iii))

2m\angle 1=180^\circ-82^\circ

2m\angle 1=98^\circ

Divide both sides by 2.

m\angle 1=\dfrac{98^\circ}{2}

m\angle 1=49^\circ

The measure of angle 1 is 49 degrees so it cannot be equal to 47 degrees.

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