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rjkz [21]
4 years ago
14

What is the first step to solving this problem: 3x-10=2(x+3)

Mathematics
2 answers:
myrzilka [38]4 years ago
8 0

Answer:

x = 16

Step-by-step explanation:

3x - 10 = 2(x+3)

<em>First step is solve this:</em>

<em>2(x+3) = 2*x + 2*3 = 2x + 6</em>

then:

3x - 10 = 2x + 6

3x - 2x = 6 + 10

x = 16

Check:

3*16 - 10 = 2(16+3)

48 - 10 = 2*19 = 38

Zielflug [23.3K]4 years ago
6 0

Answer:

x = 16

Step-by-step explanation:

you start off by isolating the variable

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Answer: The derivative would be f'(x)=2(e^{2x}-e^{-2x})

Step-by-step explanation:

Since we have given that

f(x)=(e^x+e^{-x})^{\frac{4}{2}}\\\\f(x)=(e^x+e^{-x})^2

As we will use "Chain Rule"

and at last we will use the identity ''a^2-b^2=(a-b)(a+b)''

We need to find the derivative of the function:

f'(x)=2(e^x+e^{-x})(e^x-e^{-x})\\\\f'(x)=2(e^{2x}-e^{-2x})

Hence, the derivative would be

f'(x)=2(e^{2x}-e^{-2x})

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3 years ago
50 is ____________ times as large as 5.
coldgirl [10]

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Step-by-step explanation:

3 0
3 years ago
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Express 1800 ml as percentage of 2.1 L
bagirrra123 [75]

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1400 ml is 66.67% of 2.1 L

To express one number as a percentage of another, form a fraction using these two numbers and multiply it by 100. Note that the number that is being expressed as a percentage is placed in the numerator of the fraction.

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3 years ago
Find the longer leg of the triangle.
Paha777 [63]

Answer:

Choice A. 3.

Step-by-step explanation:

The triangle in question is a right triangle.

  • The length of the hypotenuse (the side opposite to the right angle) is given.
  • The measure of one of the acute angle is also given.

As a result, the length of both legs can be found directly using the sine function and the cosine function.

Let \text{Opposite} denotes the length of the side opposite to the 30^{\circ} acute angle, and \text{Adjacent} be the length of the side next to this 30^{\circ} acute angle.

\displaystyle \begin{aligned}\text{Opposite} &= \text{Hypotenuse} \times \sin{30^{\circ}}\\ &=2\sqrt{3}\times \frac{1}{2} \\&= \sqrt{3}\end{aligned}.

Similarly,

\displaystyle \begin{aligned}\text{Adjacent} &= \text{Hypotenuse} \times \cos{30^{\circ}}\\ &=2\sqrt{3}\times \frac{\sqrt{3}}{2} \\&= 3\end{aligned}.

The longer leg in this case is the one adjacent to the 30^{\circ} acute angle. The answer will be 3.

There's a shortcut to the answer. Notice that \sin{30^{\circ}} < \cos{30^{\circ}}. The cosine of an acute angle is directly related to the adjacent leg. In other words, the leg adjacent to the 30^{\circ} angle will be the longer leg. There will be no need to find the length of the opposite leg.

Does this relationship \sin{\theta} < \cos{\theta} holds for all acute angles? (That is, 0^{\circ} < \theta?) It turns out that:

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  • \sin{\theta} = \cos{\theta} if \theta = 45^{\circ}.

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