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lakkis [162]
3 years ago
13

What is the distance between points (-42, 63) and (-39, 67)?

Mathematics
2 answers:
bekas [8.4K]3 years ago
8 0
Distance = Square Root ((X2 - X1)^2<span> + (Y2 - T1)^</span>2<span>)
</span>Distance = Square Root ((-39 --42)^2 + (67 - 63)^2<span>)
</span>Distance = Square Root ((3^2 + 4^2))Distance = Square Root (25)Distance = 5
Source:http://www.1728.org/distance.htm

mixas84 [53]3 years ago
7 0
Use the formula:

A(x_A;\ y_A);\ B(x_B;\ y_B)\\\\|AB|=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}

We have:

A(-42;\ 63);\ B(-39;\ 67)

substitute:

|AB|=\sqrt{(-39-(-42))^2+(67-63)^2}=\sqrt{3^2+4^2}\\\\=\sqrt{9+16}=\sqrt{25}=5
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3 years ago
Tan(42)= x over 16<br> I need the answer and how ya got it pleasee
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Answer:

14.40646471 =x

Step-by-step explanation:

tan (42) = x/16

Multiply each side by 16

16 tan 42 = x/16 *16

16 tan 42 = x

16 * .900404044 = x

14.40646471 =x

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Answer:253.33...

Step-by-step explanation:

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3 years ago
Let A and B be events with =PA0.7, =PB0.3, and =PA or B0.9. (a) Compute PA and B. (b) Are A and B mutually exclusive? Explain. (
kvasek [131]

Answer:

a) P(A \cup B) = P(A) +P(B) - P(A\cap B)

And if we solve for P(A \cap B) we got:

P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1

b) False

The reason is because we don't satisfy the following relationship:

P(A\cup B) = P(A) + P(B)

We have that:

0.9 \neq 0.3+0.7 =1

c) False

In order to satisfy independence we need to have the following condition:

P(A \cap B) = P(A) *P(B)

And for this case we don't satisfy this relation since:

0.1 \neq 0.7*0.3 = 0.21

Step-by-step explanation:

For this case we have the following probabilities given:

P(A) = 0.7, P(B) =0.7, P(A \cup B) =0.9

Part a

We want to calculate the following probability: P(A \cap B)

And we can use the total probability rule given by:

P(A \cup B) = P(A) +P(B) - P(A\cap B)

And if we solve for P(A \cap B) we got:

P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1

Part b

False

The reason is because we don't satisfy the following relationship:

P(A\cup B) = P(A) + P(B)

We have that:

0.9 \neq 0.3+0.7 =1

Part c

False

In order to satisfy independence we need to have the following condition:

P(A \cap B) = P(A) *P(B)

And for this case we don't satisfy this relation since:

0.1 \neq 0.7*0.3 = 0.21

4 0
3 years ago
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