What is the distance between points (-42, 63) and (-39, 67)?

2 answers:

8 0

Distance = Square Root ((X2 - X1)^2 + (Y2 - T1)^2)
Distance = Square Root ((-39 --42)^2 + (67 - 63)^2)
Distance = Square Root ((3^2 + 4^2))Distance = Square Root (25)Distance = 5
Source:http://www.1728.org/distance.htm

mixas84 [53]3 years ago

7 0

Use the formula:

$A(x_A;\ y_A);\ B(x_B;\ y_B)\\\\|AB|=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}$

We have:

$A(-42;\ 63);\ B(-39;\ 67)$

substitute:

$|AB|=\sqrt{(-39-(-42))^2+(67-63)^2}=\sqrt{3^2+4^2}\\\\=\sqrt{9+16}=\sqrt{25}=5$

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An isosceles triangle with equal sides of 5 inches and a base of 6 inches is inscribed in a circle. What is the radius, in inche

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3 years ago

Look at the picture below .thx

SVEN [57.7K]

There is no picture showing...

5 0

3 years ago

Tan(42)= x over 16 I need the answer and how ya got it pleasee

xz_007 [3.2K]

Answer:

14.40646471 =x

Step-by-step explanation: