There is no question in Part A, but i do what i can.
Part A.
We know that:
n - number of <span>packets of crackers
p -</span> <span>number of packets of pretzels
p = 2n+9
s - </span><span>number of packets of peanuts
s = 3p = 3(2n+9) = 6n+27
So:
There are 42 </span><span>packets of crackers, 93 </span><span>packets of pretzels and 279 packets of peanuts.
Part B.
x - number of rows with exactly 2 </span><span>passengers
y </span>- number of rows with exactly 3 <span>passengers
and:
There are </span><span>12 rows with exactly 2 passengers and 36 rows with exactly 3 passengers.</span>
Part A.
We know that:
n - number of <span>packets of crackers
p -</span> <span>number of packets of pretzels
p = 2n+9
s - </span><span>number of packets of peanuts
s = 3p = 3(2n+9) = 6n+27
So:
There are 42 </span><span>packets of crackers, 93 </span><span>packets of pretzels and 279 packets of peanuts.
Part B.
x - number of rows with exactly 2 </span><span>passengers
y </span>- number of rows with exactly 3 <span>passengers
and:
There are </span><span>12 rows with exactly 2 passengers and 36 rows with exactly 3 passengers.</span>