The idea is to pair up the terms, factor each sub-group, and then pull out the overall GCF to fully factor.
x^3+5x^2-6x-30
(x^3+5x^2)+(-6x-30)
x^2(x+5)+(-6x-30)
x^2(x+5)-6(x+5)
(x^2-6)(x+5)
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Answer: (x^2-6)(x+5)
Please lord thank you lord lord
Basically what you have to do is substitute the variables for the values
-4+-9+5= -8
-2-3= -5
2= 2
6-4+1= 3
-9(-2+-4--3)= 27
Answer: Unknown.
Reason:
Please provide more information on the original equation.
3√(5c)×7√(15c²)
21√(75c³)
21√(25 c² 3c)
21√(5² c² 3c)
21× 5c√(3c)
105c√(3c)
