62 can go into 584 nine times which will be 558. 584-558=26. Bring down your 1 which will now be 261. 62 can go into 261 four times which will be 248. 261-242=13. So the top answer should be, 94 R 13.
The answer might be 4 meters.
Hope this helps !
Photon
Answer:
Question 6: 26 crowns plus 15 ribbons.
Question 7: 10 footballs plus 42 basketballs.
Step-by-step explanation:
Question 6 explanation: Since the expression is 22 crowns plus 13 ribbons plus 2 ribbons plus 4 crowns, you can think of the different items as variables in an equation. Picture crowns are the variable
, and ribbons as the variable
, this will help you solve the equation in an easier way that allows you to comprehend each step better. The equation will now be
, in order to find how many
(crowns) and
(ribbons) you have, you need to combine like terms in the expression. In other words, add the terms with the variable
together, and add the terms with the variable
together. Simplified, the equation will be
. Since the variables
and
were used to represent crowns and ribbons respectively, that means the correct answer is 26 crowns plus 15 ribbons.
Question 7 explanation: You can use the same method as you did in question 6, think of footballs and basketballs as the variables
and
respectively. The equation will be
=
. Since the variable
was used to represent footballs and the variable
was used to represent basketballs, that means the correct answer would be 10 footballs plus 42 basketballs.
Answer:
Problem 1:
a. x=2
b. x=3
c. x=1
Problem 2:
A multiplication equation to hold the table true:

A division equation to hold the table true:

Step-by-step explanation:
Given in problem 1:
(a). The equation is 
It holds true for all values of
.
Let us say
,
which is greater than 1.
(b). The equation is 
It holds true for all values of
.
Let us say 
which is less than 1.
(c). The equation is 
It holds true for only
.
Let us say
,
which is equal to 1.
Problem 2:
A multiplication equation to hold the table true:

A division equation to hold the table true:

Therefore these are the values which hold true to the equation in problem 1 and 2.