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vivado [14]
3 years ago
13

A blimp provides aerial television views of a tennis game. The television camera sights the stadium at a 17degrees angle of depr

ession. The altitude of the blimp is 400m. What is the​ line-of-sight distance from the television camera to the base of the stadium​? Round to the nearest hundred meters.

Mathematics
1 answer:
BaLLatris [955]3 years ago
3 0

Answer:

1379.31meters  is the​ line-of-sight distance from the television camera to the base of the stadium​ .

Step-by-step explanation:

As given

A blimp provides aerial television views of a tennis game.

The television camera sights the stadium at a 17degrees angle of depression. The altitude of the blimp is 400m.

Now by using the trignometric identity .

sin\theta = \frac{Perpendicular}{Hypotenuse}

As the figure is given below .

Perpendicular = AC = 400 m

Hypotenuse = AB

\theta = 17^{\circ}

Putting all the values in the identity .

sin17^{\circ} = \frac{400}{AB}

0.29\ (Approx)= \frac{400}{AB}

AB= \frac{400}{0.29}

AB = 1379.31 meters

Therefore the 1379.31 meters  is the​ line-of-sight distance from the television camera to the base of the stadium​ .

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Since parallel lines have equal slope . That means slope of the required line would be .

Equation of a line passing through (a,b) and has slope m is given by :_

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