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2 years ago

Find the solution set for this equation. Separate the two values with a comma.

Mathematics

2 answers:

adelina 88 [10]2 years ago

3 0

Y^2 -11y = 0

We can factor it:
y * (y -11) = 0

So y = 11, 0

zaharov [31]2 years ago

3 0

First factor it. So the answers are (0,11)

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Help will give crown

frosja888 [35]

Answer:

This means our slope is equal to $\frac{6}{4}$ .

Step-by-step explanation:

Your ordered pairs are:

(-4, -4) and (0, 2)

To solve for the slope, we must use slope formula.

$\frac{y2-y1}{x2-x1}$

Substitute:

$\frac{2+4}{0+4}$

Solve:

$\frac{6}{4}$

This means our slope is equal to $\frac{6}{4}$ .

Hope this helped. :)

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3 years ago

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What is the third quartile of this data set 20,21,24,25,28,29,35,36,37,43,44

SashulF [63]

Answer:

Step-by-step explanation:

The data set is in ascending order, thus the median is the middle value of the data set.

median = 29

The third quartile is the middle value of the data to the right of the median

$Q_{3}$ = 37

6 0

3 years ago

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Muffins are packed and sold in boxes of 4. How many boxes are needed to pack 260 muffins?

Volgvan

Answer:

65 boxes

Step-by-step explanation:

Im not sure how to explain other then say all you do is divide 260 and 4

I hope this helped!

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3 years ago

9. A large electronic office product contains 2000 electronic components. Assume that the probability that each component operat

Marysya12 [62]

Answer:

97.10% probability that five or more of the original 2000 components fail during the useful life of the product.

Step-by-step explanation:

For each component, there are only two possible outcomes. Either it works correctly, or it does not. The probability of a component falling is independent from other components. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 2000, p = 1-0.995 = 0.005$

Approximate the probability that five or more of the original 2000 components fail during the useful life of the product.

We know that either less than five compoenents fail, or at least five do. The sum of the probabilities of these events is decimal 1. So

$P(X < 5) + P(X \geq 5) = 1$

We want $P(X \geq 5)$

$P(X \geq 5) = 1 - P(X < 5)$

In which

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2000,0}.(0.005)^{0}.(0.995)^{2000} = 0.000044$

$P(X = 1) = C_{2000,1}.(0.005)^{1}.(0.995)^{1999} = 0.000445$

$P(X = 2) = C_{2000,2}.(0.005)^{2}.(0.995)^{1998} = 0.002235$

$P(X = 3) = C_{2000,3}.(0.005)^{3}.(0.995)^{1997} = 0.007480$

$P(X = 4) = C_{2000,4}.(0.005)^{4}.(0.995)^{1996} = 0.018765$

$P(X < 5) = P(X = 0) + `P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.000044 + 0.000445 + 0.002235 + 0.007480 + 0.018765 = 0.0290$

$P(X \geq 5) = 1 - P(X < 5) = 1 - 0.0290 = 0.9710$

97.10% probability that five or more of the original 2000 components fail during the useful life of the product.

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2 years ago

What is 1+1? Wrong answers only

pishuonlain [190]

Answer:

Step-by-step explanation:

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2 years ago

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