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UNO [17]
3 years ago
15

Which even number is not a composite number? A. 8 B. 6 C. 4 D. 2

Mathematics
1 answer:
dedylja [7]3 years ago
6 0
The answer is for this is D. 

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Pani-rosa [81]

Answer:if this helps it’s -3/2 and the slope is 8 :) C is the best answer!

Step-by-step explanation:

6 0
3 years ago
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3/4 (4y+8)= 5+3y<br> solve for y:<br> please help
4vir4ik [10]

Answer:

No Soultion

Step-by-step explanation:

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8.27 Any quarter has a face value of $0.25. An eccentric collector offers to buy state quarters for 600% of their face value. At
Svetach [21]

Answer:

$7.50

Step-by-step explanation:

First we find what is the value at which the eccentric collector offers to buy the quarters for. We know the value at which they will buy the quarter for is 600% of the face value - which is $0.25.

Now we do some math and find the value at which the person will buy the quarter for is $1.50.

Now we multiply the value by 50 since Larry would be giving 50 quarters.

$1.50*50 = 7.50

So, Larry will receive $7.50 for selling his 50 quarters to the eccentric collector.

4 0
2 years ago
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Factor 2x^3 +x^2-15x-18
chubhunter [2.5K]

Factor the polynomial

(x-3)(2x+3)(x+2)

7 0
3 years ago
Find the value of c so that (x+2) is a factor of the polynomial<br><br> p(x)=3x^4-x^2+cx-2
DedPeter [7]
Using polynomial long division, we get
         
         3x^3+6x^2+11x
         _____________
(x+2) | 3x^4-x^2+cx-2
          -(3x^4+6x^3)
          ____________
             6x^3-x^2+cx-2
          - (6x^3+12x^2)
         _____________
        11x^2+cx-2
      -(11x^2+22x) 
       __________
        (22+c)x-2. 

If you're wondering how I did the long division, what I essentially did was get the first value (at the start, it was 3x^4) and divided it by the first value of the divisor (which in x+2 was x) to get 3x^3 in our example. I then subtracted the polynomial by the whole divisor multiplied by, for example, 3x^3 and repeated the process.

For this to be a perfect factor, (x+2)*something must be equal to (22+c)x-2. Focusing on how to cancel out the 2, we have to add 2 to it. To add 2 to it, we have to multiply (x+2) by 1. However, there's a catch, which is that we subtract whatever we multiply (x+2) by, so we have to multiply it by -1 instead. We still need to cross out (22+c)x. Multiplying (x+2) by -1, we get
(-x-2) but by subtracting the whole thing from something means that we have to add -(-x-2)=x+2 to something to get 0. x+2-x-2=0, xo (22+c)x-2 must equal -x-2, meaning that (22+c)=-1 and c=-23
4 0
3 years ago
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