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3 years ago

13

A publishing company is going to have 24,000 books printed. There are between 3 and 4 books out of ever 3,000 that will have a p

rinting error. At this rate, which number could be the exact number of books that will have a printing error?
a. 7
b. 12
c. 31
d. 36

1 answer:

vazorg [7]3 years ago

4 0

The exact number of books that will have a printing error is C.31

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Kim finds a 1-meter tree branch and marks it off in thirds and fifths. She then breaks the branch along all the markings and rem

True [87]

Answer:

3/5

Step-by-step explanation:

We want to find the fraction of the original branch that remains, so we will assume a length of the branch in order to make our calculation easier.

Since Kim marks it off in thirds and fifths, let's find the least common multiple of 3 & 5.

Least common multiple of 3 & 5 is 15.

Thus,let's make the length of the branch to be 15-meter long.

Now, if the branch is 15 m long, considering the markings of thirds and fifths, the branch would be cut at:

3, 5, 6, 9, 10, 12 meters.

We are told that She then breaks the branch along all the markings and removes one piece of every distinct length. Thus;

Distinct lengths are;

3 metres

5 - 3 = 2 metres

10 - 9 = 1 meter

Total she removes = 3 + 2 + 1 = 6 meters.

Total remaining is;

15 - 6 = 9 meters

Expressing this as a fraction of the original branch gives:

9/15

Divide both numerator and denominator by 3 to get; 3/5

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2 years ago

F(-1)=-3 and g(-1)=5

valentinak56 [21]

Answer:

What do you have to do what is the question asking

Step-by-step explanation:

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3 years ago

An electronic product contains 48 integrated circuits. The probability that any integrated circuit is defective is 0.01, and the

BigorU [14]

Answer:

0.6173 = 61.73% probability that the product operates.

Step-by-step explanation:

For each integrated circuit, there are only two possible outcomes. Either they are defective, or they are not. The integrated circuits are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

An electronic product contains 48 integrated circuits.

This means that $n = 48$

The probability that any integrated circuit is defective is 0.01.

This means that $p = 0.01$

The product operates only if there are no defective integrated circuits. What is the probability that the product operates?

This is P(X = 0). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{48,0}.(0.01)^{0}.(0.99)^{48} = 0.6173$

0.6173 = 61.73% probability that the product operates.

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3 years ago

the data in the table below represents a linear relationship . what is the missing piece of data table and answer choices will b

Gennadij [26K]

C) 2

1) Given the table, let's find out that missing data picking 2 points (2,-10) and (6,-4)

Since we have the slope, let's work on finding the linear coefficient

plugging point (2,-10) into that:

y= mx +b

-10 =3/2(2) +b

-10 =6/2 +b

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2) So the rule of that function is y= 3/2x -13

Plugging x= 10 we have

y= 3/2(10) -13

y=2

3) So the missing y-coordinate is 2.

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1 year ago

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Veronika [31]

Answer:

Step-by-step explanation:

The 1 choice. The events are independent because P(red) ×P(green)= P(red and green)

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3 years ago

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