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2 years ago

Ignore the highlighted ones please thxs

Mathematics

2 answers:

scoundrel [369]2 years ago

6 0

Answer: i think that it is D. 2/3

Step-by-step explanation:

denis23 [38]2 years ago

5 0

I believe it’s D. 2/3

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Philip has $2,000 and spends $23.75 on supplies. He divides the remaining amount equally among his 8 employees. How much does ea

Eddi Din [679]

$2,000 - $23,75 = $1,976.25 / 8 = $<span>247.03 each</span>

5 0

3 years ago

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Write an equation to model this proportional relationship, where x represents the length of the rectangle and y represents the w

Kay [80]

When Area of rectangle is constant, then the length x is inversely proportional to the width y of the rectangle.

$x\propto \frac{1}{y}$

We know that the area of a rectangle is given by the product of the length and width of the rectangle.

Area = Length*Width

In this given problem,

The length of the rerectanglctangle is represented by x

and the width of the rectangle is represented by y

If the area of the rectangle is represented by A now.

So by the formula,

A = x*y

When A is constant then,

x = A/y

$\therefore x \propto \frac{1}{y}$

So from the above calculation we can conclude that about relation between length and width that,

"When Area of rectangle is constant, then the length x is inversely proportional to the width y of the rectangle."

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5 0

1 year ago

An aircraft has a maximum of 30 first class seats and 220 economy seats.

guajiro [1.7K]

Answer:

x<y first inequality

x>y second inequality

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5 0

3 years ago

Given vectors u = -9i + 8j and v= 7i + 5j find 2u -6v in terms of unit vectors i and j

Aloiza [94]

Answer: - 60i - 14j

Step-by-step explanation:

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7 0

2 years ago

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Solve the initial value problem: y'(x)=(4y(x)+25)^(1/2) ,y(1)=6. you can't really tell, but the '1/2' is the exponent

goblinko [34]

Answer:

$y(x)=x^2+5x$

Step-by-step explanation:

Given: $y'=\sqrt{4y+25}$

Initial value: y(1)=6

Let $y'=\dfrac{dy}{dx}$

$\dfrac{dy}{dx}=\sqrt{4y+25}$

Variable separable

$\dfrac{dy}{\sqrt{4y+25}}=dx$

Integrate both sides

$\int \dfrac{dy}{\sqrt{4y+25}}=\int dx$

$\sqrt{4y+25}=2x+C$

Initial condition, y(1)=6

$\sqrt{4\cdot 6+25}=2\cdot 1+C$

$C=5$

Put C into equation

Solution:

$\sqrt{4y+25}=2x+5$

$4y+25=(2x+5)^2$

$y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}$

$y(x)=x^2+5x$

Hence, The solution is $y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}$ or $y(x)=x^2+5x$

4 0

2 years ago