All categories

4 years ago

3.1 × 10^-4 in standard form

Mathematics

1 answer:

podryga [215]4 years ago

4 0

Answer:

Its 0.00031

Step-by-step explanation:

You just move your decimal the number of exponent. In your case -4 so you would move it to the left because it's a negative and move it 4 spaces.

Hope this helps!

You might be interested in

What is bigger 1/4 or 0.4 or are they equal

victus00 [196]

They are equal because if you divide 4÷1.0 your answer would be 0.4

8 0

3 years ago

Read 2 more answers

The volume of a sphere is 113.1 cm3; find the diameter of the sphere.

Dennis_Churaev [7]

Answer:

del

Step-by-step explanation:

7 0

3 years ago

What’s the equation for 4.

avanturin [10]

Answer:

X=3

Step-by-step explanation:

11=3(X × ⅓) +8

11=3(X/3) +8

11-8=X

X=3

4 0

4 years ago

Read 2 more answers

Guys I need help! You and your friend are rolling number cubes. Each cube has 6 sides with the numbers 1 to 6. If a sum of 7 is

olga nikolaevna [1]

Friend 3 is right like really right 18 and you 18 2,3,4

5 0

2 years ago

Sand pouring from a chute forms a conical pile whose height is always equal to the diameter. If the height increases at a consta

Cerrena [4.2K]

Answer:

$125\pi \frac{\text{ft}^3}{\text{min}}$ .

Step-by-step explanation:

Let x represent height of the cone.

We have been given that Sand pouring from a chute forms a conical pile whose height is always equal to the diameter.

We know that radius is half the diameter, so radius of cone would be $\frac{x}{2}$ .

We will use volume of cone formula to solve our given problem.

$V=\frac{1}{3}\pi r^2h$

Upon substituting the value of height and radius in terms of x, we will get:

$V=\frac{1}{3}\pi (\frac{x}{2})^2(x)$

$V=\frac{1}{3}\pi\frac{x^2}{4}(x)$

$V=\frac{1}{12}\pi x^3$

Now, we will take the derivative of volume with respect to time as:

$\frac{dV}{dt}=\frac{1}{12}\pi\cdot 3x^2\cdot \frac{dx}{dt}$

$\frac{dV}{dt}=\frac{1}{4}\pi\cdot x^2\cdot \frac{dx}{dt}$

Upon substituting $x=10$ and $\frac{dx}{dt}=5$ , we will get:

$\frac{dV}{dt}=\frac{1}{4}\pi\cdot (10)^2\cdot 5$

$\frac{dV}{dt}=\frac{1}{4}\pi\cdot 100\cdot 5$

$\frac{dV}{dt}=\pi\cdot 25\cdot 5$

$\frac{dV}{dt}=125\pi$

Therefore, the sand is pouring from the chute at a rate of $125\pi \frac{\text{ft}^3}{\text{min}}$ .

8 0

3 years ago