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3 years ago

8

Catapillar is 2.15 inches long a Nother caliphate older is 1.9 inches long Robert you say quite picture do you find the cut by d

id leave leave of the caliphate where does Robert work makes it explain why or why not

1 answer:

saw5 [17]3 years ago

7 0

You messed up your writing on this question I can't help.if I can't read it

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Solve x(−2) 2 =4(−2)

Simora [160]

Hi there,

X x (-2) x 2 = 4 x (-2)
- x = - 2

Hence, X = 2

Hope this helps :)

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3 years ago

Please answer asap...

Anon25 [30]

Answer:

The answer is B - 288

To get this answer all you need to do is

First, subtract 316 - 28 to get your answer :)

Hope this helps!

-sofia~

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3 years ago

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Using place value how to increase 2384598 by six million

Leno4ka [110]

6 million = 6,000,000

2,384,598 + 6,000,000 = 8,384,598

your answer is 8,384,598

hope this helps

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3 years ago

What is the area of this triangle ?

oee [108]

Answer:

Area of triangle is 9.88 units^2

Step-by-step explanation:

We need to find the area of triangle

Given E(5,1), F(0,4), D(0,8)

We will use formula:

$Area\,\,of\,\,triangle =\sqrt{s(s-a)(s-b)s-c)} \\where\,\, s = \frac{a+b+c}{2}$

We need to find the lengths of side DE, EF and FD

Length of side DE = a = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side DE = a = $=\sqrt{(5-0)^2+(1-8)^2}\\=\sqrt{(5)^2+(-7)^2}\\=\sqrt{25+49}\\=\sqrt{74}\\=8.60$

Length of side EF = b = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side EF = b = $=\sqrt{(0-5)^2+(4-1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\=5.8$

Length of side FD = c = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side FD = c = $=\sqrt{(0-0)^2+(8-4)^2}\\=\sqrt{(0)^2+(4)^2}\\=\sqrt{0+16}\\=\sqrt{16}\\=4$

so, a= 8.60, b= 5.8 and c = 4

s = a+b+c/2

s= 8.6+5.8+4/2

s= 9.2

Area of triangle= $=\sqrt{s(s-a)(s-b)s-c)}\\=\sqrt{9.2(9.2-8.6)(9.2-5.8)(9.2-4)}\\=\sqrt{9.2(0.6)(3.4)(5.2)}\\=\sqrt{97.5936}\\=9.88$

So, area of triangle is 9.88 units^2

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3 years ago

17-2 (6-4)(7-3)-7. worth 10 points

Leni [432]

17-2(6-4)(7-3)-7
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2 years ago

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