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3 years ago

Can you tell de answer?

Mathematics

1 answer:

kodGreya [7K]3 years ago

7 0

Yes, it’s D because you would have want to compare both fractions by making them have the same denominator. Since 60 is the least common denominator for 10 and 12 (the denominators), you would convert the fractions by multiplying the numerator and denominator of 5/10 by 6 to get 60. 5/10 would turn into 30/60. Then you would multiply 6/12 both by 5, and then it would turn into 30/60. Now that you have equal fractions, you can guess that they are the same. Therefore, 30/60=30/60! An easier way of doing it would be just simplifying them into 1/2 and comparing them + seeing that they are both 1/2. Hope this helps!

•••

Caramelatte

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Write the equation of the circle with a center at (11,6) and a radius of 6.

andrew11 [14]

Answer:

(x-11)^2 + (y-6)^2= 6^2

Step-by-step explanation:

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3 years ago

Read 2 more answers

10. A manufacturer wanted to know if more coupons would be redeemed if they were mailed to the

Mandarinka [93]

Using the t-distribution, it is found that the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is no difference, that is, the mean is of 0, hence:

$H_0: \mu = 0$

At the alternative hypothesis, it is tested if the mean number is greater for females, that is, the mean is greater than 0, hence:

$H_1: \mu > 0$

<h3>What is the test statistic?</h3>

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.

$\mu$ is the value tested at the null hypothesis.

s is the standard deviation of the sample.

n is the sample size.

In this problem, the parameters are given as follows:

$\overline{x} = 1.5, \mu = 0, s = 4.75, n = 50$ .

Hence, the test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{1.5 - 0}{\frac{4.75}{\sqrt{50}}}$

t = 2.23

<h3>What is the conclusion?</h3>

Considering a <em>right-tailed test</em>, as we are testing if the mean is greater than a value, with a <em>significance level of 0.01 and 50 - 1 = 49 df</em>, the critical value is given by $t^{\ast} = 2.4$ .

Since the test statistic is less than the critical value for the right-tailed test, the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

More can be learned about the t-distribution at brainly.com/question/26454209

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2 years ago

Find BC round to the nearest tenth

slega [8]

Answer:

6.7

Step-by-step explanation:

Here, we can apply cosine law, $c^2=a^2+b^2-2abcos\theta$