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kompoz [17]
3 years ago
6

Simplify radical using the exponent rule. Show work

Mathematics
1 answer:
katen-ka-za [31]3 years ago
8 0

Answer:

\frac{1}{x^{4} }

Step-by-step explanation:

(\sqrt[3]{x^{2} } × \sqrt[6]{x^{4}})⁻³

\sqrt[3]{x^{2} } is the same thing as x^{\frac{2}{3} }

you can think of the numerator as the power and the denominator as the root

rewrite both terms:

(x^{\frac{2}{3} } × x^{\frac{4}{6} })⁻³

simplify the 4/6:

(x^{\frac{2}{3} } × x^{\frac{2}{3} })⁻³

bases are the same, add the exponents:

(x^{\frac{4}{3} })⁻³

multiply the exponents:

x^{\frac{-12}{3} }

simplify:

x⁻⁴

negative power rule:

\frac{1}{x^{4} }

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Answer: (2x+5)(2x−5)

Step-by-step explanation:For me, what i like to do is to try divide the problem into two parts. For example in this problem, you would divide the 4x^2 into two 4x(since 4x+4x = 4x^2). Then 25 can be divide into into 5s (5x5=25). SInce you know that its a negative 25, you know that it has to be a negative on one of the sides. So the answer in factor form is (2x+5)(2x−5)

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3 years ago
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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guapka [62]

Answer:

  2

----------

5w^11


Step-by-step explanation:

8/20 reduces to 2/5, and (w^(-2)) / w^9 becomes 1 / w^11.

Overall, #20 reduces to:

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