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kompoz [17]
3 years ago
6

Simplify radical using the exponent rule. Show work

Mathematics
1 answer:
katen-ka-za [31]3 years ago
8 0

Answer:

\frac{1}{x^{4} }

Step-by-step explanation:

(\sqrt[3]{x^{2} } × \sqrt[6]{x^{4}})⁻³

\sqrt[3]{x^{2} } is the same thing as x^{\frac{2}{3} }

you can think of the numerator as the power and the denominator as the root

rewrite both terms:

(x^{\frac{2}{3} } × x^{\frac{4}{6} })⁻³

simplify the 4/6:

(x^{\frac{2}{3} } × x^{\frac{2}{3} })⁻³

bases are the same, add the exponents:

(x^{\frac{4}{3} })⁻³

multiply the exponents:

x^{\frac{-12}{3} }

simplify:

x⁻⁴

negative power rule:

\frac{1}{x^{4} }

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son4ous [18]

Answer:

B

Step-by-step explanation:

7-3=4

4x4=16

6 0
3 years ago
Michael canned 4,713 quarts of blueberries over the summer. By the end of the year he had used 1/3 of what he had canned. How ma
aleksandr82 [10.1K]

Answer:

he used 1,571

Step-by-step explanation:

if you divide 4,713 by 3, you get 1,571 and that amount is equal to just 1/3 of the amount.

3 0
3 years ago
Find the midpoint of the segment with the following endpoints.<br> (2,9) and (8,1)
vazorg [7]

Answer:

\displaystyle (5,5)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)
  • Midpoint Formula: \displaystyle (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Step-by-step explanation:

<u>Step 1: Define</u>

Point (2, 9)

Point (8, 1)

<u>Step 2: Identify</u>

(2, 9) → x₁ = 2, y₁ = 9

(8, 1) → x₂ = 8, y₂ = 1

<u>Step 3: Find Midpoint</u>

Simply plug in your coordinates into the midpoint formula to find midpoint

  1. Substitute in points [Midpoint Formula]:                                                         \displaystyle (\frac{2+8}{2},\frac{9+1}{2})
  2. [Fractions] Add:                                                                                                  \displaystyle (\frac{10}{2},\frac{10}{2})
  3. [Fractions] Divide:                                                                                              \displaystyle (5,5)
7 0
3 years ago
Is X-1 a factor of x^5-1?
Musya8 [376]

Answer: No

Explanation:

According to factor theorem, if f(x)=0 then x is a factor of the given function or equation.

As x-1 is a factor

We equate x-1=0

x=1

Substituting in x^5-1, we have 1^5-1 =1-1=0.

Hence, it's a factor.

When coming to x^5+1, it would become 1^5+1=1+1=2

So x-1 isn't a factor of x^5+1.

4 0
2 years ago
What is the solution of the system of equations? y = –3x + 8 y = –5x – 2
jekas [21]
y=-3x+8 \\ y=-5x-2 \\  \\ -3x+8=-5x-2 \\ -3x+5x=-2-8 \\ 2x=-10 \\ x=- \frac{10}{2}  \\ x=-5 \\ y=-3(-5)+8=15+8=23  \\ \\ \boxed{-5,23}
6 0
3 years ago
Read 2 more answers
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