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3 years ago

I feel so stupid, how do you change a fraction into a mix number???

Mathematics

1 answer:

Vlad [161]3 years ago

7 0

Answer:

Divide the numerator by the denominator. Your answer would be the whole number, and the remainder would be your fraction.

I have also clipped a picture from fractionfun.com to make it more clear.

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Two polygons are similar. What is the correct similarity statement?<br>

joja [24]

Answer:

option 3

Step-by-step explanation:

Given the 2 triangles are similar then corresponding angles are congruent.

Calculate the missing angles in both triangles.

∠ A = 180° - (90 + 35)° = 180° - 125° = 55°

∠ L = 180° - (90 + 55)° = 180° - 145° = 35°

Consider ACB ~ MNL , comparing corresponding angles

∠ A= 55° and ∠ M = 90° ← not congruent

Consider ABC ~ LMN, comparing corresponding angles

∠ A = 55° and ∠ L = 35° ← not congruent

Consider CBA ~ LMN , comparing corresponding angles

∠ C = 35° and ∠ L = 35° ← congruent

∠ B = 90° and ∠ M = 90° ← congruent

∠ A = 55° and ∠ N = 55° ← congruent

The correct similarity statement is

CBA ~ LMN

6 0

3 years ago

Read 2 more answers

Consider the following game, played with three standard six-sided dice. If the player ends with all three dice showing the same

ddd [48]

Answer:

$P(A) = \frac{1}{36}$

$P(B) = \frac{15}{36}$

$P(U) = \frac{11}{36}$

Step-by-step explanation:

From the question we are told that

The number of dice is $n = 3$

Generally for all three dice to show the same number the second and the third dice must have the same outcome as the outcome of the first dice.

This means that the number of outcome the first die can have is 6 (6 sides), the number of outcome which the second and the third dice can have is 1 (they must match the first )

So the probability that all three dice show the same number on the first roll is mathematically represented as

$P(A) = \frac{6}{6} * \frac{1}{6} * \frac{1}{6}$

=> $P(A) = \frac{1}{36}$

Generally for two of the three dice show the same number after the first roll then the number of outcome for one of the dice would be is 6 , the number of outcome for another one must be 1(i.e it must match the first ) , the number of outcome for the remaining one must be 5 (i.e it can show any of the remaining 5 sides which the first and second dice are not showing )

Now the number of ways of selecting this 2 dice that show the same number from the 3 dice is mathematically represented as

$N = ^3C_2$

Here C stands for combination

$N = ^3C_2 = 6$

So the probability that exactly two of the three dice show the same number after the first roll is mathematically represented as

$P(B) = N \frac{1}{6} * \frac{5}{6}$

=> $P(B) = \frac{15}{36}$

Generally from the question we are told that if two dice match, the player re-rolls the die that does not match.

Now the probability that the die that did not match the first time will match the second time is

$P(E ) = \frac{1}{6}$

Generally if that one die does not show the same number in the second round , the probability that it will match in the third round is

$P(R) = \frac{5}{6} * \frac{1}{6}$

Generally the probability that he wins (i.e when all three are showing the same number ) and exactly two is showing the same number is mathematically represented as

$P(K) = P(E)* P(B) + P(R)* P(B)$

=> $P(K) = \frac{1}{6} * \frac{15}{36} + \frac{5}{6} * \frac{1}{6} * \frac{15}{36}$

=> $P(K)= \frac{165}{1296}$

So the probability that the player wins, conditioned on exactly two of the three dice showing the same number after the first roll is mathematically represented as

$P(U) = \frac{\frac{165}{1296}}{\frac{15}{36} }$

=> $P(U) = \frac{11}{36}$

6 0

4 years ago

How are different ideas about geometry connected?

Margarita [4]

They areall related to geoemtry

8 0

4 years ago

Lf f(x) = 5x, what is f^-1(x)?

Nonamiya [84]

Answer: $f^{-1}(x)=\frac{x}{5}$

Step-by-step explanation:

By definition the domain of an inverse function $f^-1(x)$ is the range of f(x) and the range of the inverse function is equal to the domain of the principal function f(x).