Solve for x: 3 < x + 3 < 6 45 points.

Mathematics

2 answers:

Bezzdna [24]3 years ago

8 0

Answer:

0 < x < 3

Step-by-step explanation:

3 < x + 3 < 6

Subtract 3 across the inequality

3 - 3 < x + 3 - 3 < 6 - 3

0 < x < 3

irinina [24]3 years ago

3 0

Answer:

0 < x < 3

Step-by-step explanation:

3 < x + 3 < 6 (Subtract 3 from all terms)

0 < x < 3 (The third option is the answer)

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ArbitrLikvidat [17]

Answer: y=-4x+13

Explanation : because it is :)

4 0

2 years ago

z varies directly with x and inversely with y^2. When x = 2 and y = 5, z = 8. What is the value of z when x = 4 and y = 9?

Ivanshal [37]

Direct variation is y = kx

Inverse variation is y = k/y

if z varies directly with x, then the equation would be z = kx

if z varies inversely with y^2 then the equation would be z = k/y^2. Combining, these two, we have z = kx/y^2

We use the first set of values to find the constant k:

x = 2, y = 5, z = 8:

8 = 2x/25, k = 100. Now we use the second set of values to find z:

x = 4, y = 9, k = 100 and z is unknown:

z = (4X100)/9^2

z = 400/81--> this is your final final answer.

*plz rate brainliest

4 0

3 years ago

Read 2 more answers

Please help me with this question

adoni [48]

Answer:

$y = e^{x^2 - 3x}\\\\\\Let \ u = x^2 - 3x\\\\y = e^u\\\\\frac{dy}{du} = e^u\\\\\frac{du}{dx} = 2x - 3\\\\y' = \frac{dy}{dx} = \frac{dy}{du} *\frac{du}{dx} = e^u * (2x -3)\\\\Substitute \ u = x^2 -3\\\\y' = (2x -3)e^{x^2-3x}\\\\option A$