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scoray [572]
3 years ago
9

Find the mean, median, mode, and range of this data: 49, 49, 54, 55, 52, 49, 55. If necessary, round to the nearest tenth.

Mathematics
2 answers:
True [87]3 years ago
7 0

Answer:

Mean=51.86

Mode=49

Median=52

Range=6

Step-by-step explanation:

We are given a data set:

49, 49, 54, 55, 52, 49, 55

We arrange this in ascending order:

49,49,49,52,54,55,55

Mean=sum of all the elements/number of elements

         =49+49+49+52+54+55+55/7

Mean  =51.86

Mode is that element of the data set which has highest frequency i.e. the element which comes most.

Hence, Mode=49

Median is the middle element of the data set arranged in ascending order.

Hence, Median=52

Range=highest element-lowest element

Hence, Range=55-49

            Range=6

Darya [45]3 years ago
3 0
Mean: 51.9
Median: 52
Mode: 49
Range: 6
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Solve the inequality -5(d-2)>35
chubhunter [2.5K]

Answer:

d < -5

Step-by-step explanation:

Okay, so the equation is  -5(d-2)>35

First we have to use distributive property to get rid of the parenthesis.

we do -5(d) --> -5d

then, -5(-2) --> 10

So now we just redo the equation---

-5d + 10 > 35

now you have to isolate d, the variable

First, to isolate you have to get rid of 10. Subtract 10 on both sides.

-5d + 10 > 35

      - 10    -10

----------------------

-5d       >  25

Then you have -5d > 25. You have to do the opposite operation again to make the d by itself, so you divide -5 on each side.

   -5d > 25

   -----    -----

    -5       -5

-5d/-5 is d because the -5's cancel out. 25/-5 is -5. Now, you have to flip the equation because when working with inequalities, you have to flip the symbol.

SO,,, the answer is

d < -5

Hope this helps!!

-Ketifa

8 0
3 years ago
a. Verify that the given point lies on the curve. b. Determine an equation of the line tangent to the curve at the given point.
xxMikexx [17]

Answer:

y = 13*( -x/9 + 1/5)

Step-by-step explanation:

Given:

- The curve has an equation as follows:

                               44 = 5x^2 + 3xy + 3y^2

Find:

a. Verify that the given point (2​,2​) lies on the curve.

b. Determine an equation of the line tangent to the curve at the given point.

Solution:

- To verify whether the point lies on the given curve we will substitute the coordinates of the point into the equation as follows:

                              44 = 5*(2)^2 + 3*(2)(2) + 3*(2)^2

                              44 = 20 + 12 + 12

                              44 = 44 ......Hence proven.

- The equation of the line tangent to the curve is expressed as a linear function as follows:

                              y = m*x + C

Where, m is the gradient of the line.

            C is the y-intercept.

                              m = Δy / Δx = dy/dx

- We will take the derivative of the given curve with respect to x as follows:

                             0 = 10x + 3*( y + xy' )  + 6y*y'\\\\-10x - 3y = y' ( 3x + 6y)\\\\ y' = - \frac{10x + 3y}{3x + 6y}

- Evaluate y' at the point (2,2) we get:

                            y' = - ( 10(2) + 3(2) ) / ( 3(2) + 6(2) )

                            y' = - ( 26 ) / (18)

                            y'= m = - 13/9

- To evaluate C, we will use the point (2,2) for linear expression above with m as follows:

                            y = -13*x/9 + C

                            2 =-13*(2)/9 + C

                            C = 13 / 5

- The equation of the tangent is as follows:

                            y = 13*( -x/9 + 1/5)  

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