Question

Abcd is a rectangle. Find the length of each diagonal. .AC= 3y/5 BD=3y-4

Answer 1

Answer:

AC = BD = 1 unit

Step-by-step explanation:

 Given : length of diagonal of rectangle ABCD  $AC=\frac{3y}{5}$ and $BD=3y-4$

We have to find the length of diagonal.

We know In rectangle diagonal are of equal lengths.

Therefore, for rectangle ABCD diagonals AC= BD

Substitute the values, we get,

$\frac{3y}{5}=3y-4$

Cross multiply , we get

$3y=5(3y-4)$

On simplyfy , we get

$3y=15y-20$

Solve for y , we get

$15y-3y=20$

$12y=20$

Divide both side by 12, we get,

$y=\frac{20}{12}=\frac{10}{6}$

Thus, put the values of y in AC and BD to find the length of diagonals , we get,

$AC=\frac{3y}{5}=\frac{3}{5}\times\frac{10}{6}=1$

Similarly for BC, we get,

$BD=3y-4=3(\frac{10}{6})-4=5-4=1$

Thus, AC = BD = 1 unit

Answer 2

I hope this helps you