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Rasek [7]
3 years ago
13

Abcd is a rectangle. Find the length of each diagonal. .AC= 3y/5 BD=3y-4

Mathematics
2 answers:
34kurt3 years ago
4 0

Answer:

AC = BD = 1 unit

Step-by-step explanation:

 Given : length of diagonal of rectangle ABCD  AC=\frac{3y}{5} and BD=3y-4

We have to find the length of diagonal.

We know In rectangle diagonal are of equal lengths.

Therefore, for rectangle ABCD diagonals AC= BD

Substitute the values, we get,

\frac{3y}{5}=3y-4

Cross multiply , we get

3y=5(3y-4)

On simplyfy , we get

3y=15y-20

Solve for y , we get

15y-3y=20

12y=20

Divide both side by 12, we get,

y=\frac{20}{12}=\frac{10}{6}

Thus, put the values of y in AC and BD to find the length of diagonals , we get,

AC=\frac{3y}{5}=\frac{3}{5}\times\frac{10}{6}=1

Similarly for BC, we get,

BD=3y-4=3(\frac{10}{6})-4=5-4=1

Thus, AC = BD = 1 unit

-Dominant- [34]3 years ago
3 0
I hope this helps you

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Answer:

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The sketch of the level curves can be see in the attached image below.

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