I'm pretty sure it'd be 4/6 and then it'd simplify to 2/3. You add together the possibilities of rolling an odd number (3/6) to the possibilities of getting a number less than 3 (2/6) and then subtract the number that they both had in common (which would've been the number 1). So it'd be 3/6+2/6=5/6 - 1/6. and you'd get 2/3
Answer:
2299 in^2
Step-by-step explanation:
The formula for the volume of a square pyramid of base A and height h is
V = (A)(h).
Here, the perimeter of the base is 44 inches, so that the length of one side must be (44 in) / 4, or 11 in. The area of a square of side s is A = s^2, so we have:
Here, V = (11 in)^2 * (19 in) = 2299 in^2
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➷ You may have forgotten to add the options
However, you can collect like terms
In other words, collect the 'x' values and collect the numbers
5x + 18x = 23x
-12 - 4 = -16
Thus, your answer would be 23x - 16.
Any further questions, let me know.
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Answer:
<em>(1, - 2) </em>
Step-by-step explanation:
2x - y = 4
3x + y = 1
A = ![\left[\begin{array}{cc}2&-1\\3&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-1%5C%5C3%261%5Cend%7Barray%7D%5Cright%5D)
= 2(1) - 3( - 1) =2 + 3 = 5
= ![\left[\begin{array}{cc}4&-1\\1&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D4%26-1%5C%5C1%261%5Cend%7Barray%7D%5Cright%5D)
= 4(1) - 1(- 1) = 4 + 1 = 5
= ![\left[\begin{array}{cc}2&4\\3&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%264%5C%5C3%261%5Cend%7Barray%7D%5Cright%5D)
= 2(1) - 4(3) = 2 - 12 = - 10
<em>x </em>= 
=<em> 1</em>
<em>y </em>= 
= <em>- 2</em>
<em>(1, - 2)</em>
Answer:
(-infinity, infinity)
Step-by-step explanation:
I assume it's y = 2x-6 which is a linear function. The line goes on forever.
