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ra1l [238]
3 years ago
14

XYZ Company declares dividends of $50,000. Samuel Smith owns 50 shares of stock. The company has sold 25,000 total shares of sto

ck. What is Sam's share of the declared dividends?
Mathematics
2 answers:
elena55 [62]3 years ago
4 0
Samuel will get $100 from the comp
dimulka [17.4K]3 years ago
4 0

Answer:

Hence, Sam's share of the declared dividends is $100.

Step-by-step explanation:

XYZ Company declares dividends of $50,000.

<em>Samuel Smith owns 50 shares of stock.</em>

The company has sold 25,000 total shares of stock.

That means $50,000 is to be divided into 25000 so that we get the cost of 1 share.

cost of 25000 shares= $50,000

cost of 1 share=$ (50,000/25,000)= $ 2.

Hence cost of 50 shares=$ (2×50)=$100.

Hence, Sam's share of the declared dividends is $100.

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Brent sells an avarage of 52 pot holders each week. about how many pot holders does he sell in 58 weeks.
Inessa [10]

The amount of pot holders Brent sold for 58 weeks is 3016

<h3>How to find the amount of pot holders Brent sold?</h3>

He sells 52 pot holders each week.

This means for every week, he sold 52 pot holders. Therefore, the amount of pot holders he sold for 58 weeks can be solved as follows:

1 week = 52 pot holders

58 weeks  = ?

cross multiply

number of pot sold for 58 weeks = 58 × 52

number of pot sold for 58 weeks = 3016

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6 0
2 years ago
Naomi plans to attend a four-year college that costs a total of $21,800 per year. Her family invests $9,500 in an account that e
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Answer:

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Step-by-step explanation:

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4 0
3 years ago
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Sum or difference of<br> 7/8 + 1/3
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Calculate the flux of the vector field F⃗ (x,y,z)=(exy+9z+4)i⃗ +(exy+4z+9)j⃗ +(9z+exy)k⃗ through the square of side length 3 wit
ikadub [295]

The square (call it S) has one vertex at the origin (0, 0, 0) and one edge on the y-axis, which tells us another vertex is (0, 3, 0). The normal vector to the plane is \vec n=\vec\imath-\vec k, which is enough information to figure out the equation of the plane containing S:

(x\,\vec\imath+y\,\vec\jmath+z\,\vec k)\cdot(\vec\imath-\vec k)=0\implies x-z=0\implies z=x

We can parameterize this surface by

\vec s(x,y)=x\,\vec\imath+y\,\vec\jmath+x\,\vec k

for 0\le x\le\frac3{\sqrt2} and 0\le y\le3. Then the flux of \vec F, assumed to be

\vec F(x,y,z)=(e^{xy}+9z+4)\,\vec\imath+(e^{xy}+4z+9)\,\vec\jmath+(9ze^{xy})\,\vec k,

is

\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\iint_S\vec F(\vec s(x,y))\cdot\vec n\,\mathrm dx\,\mathrm dy

=\displaystyle\int_0^3\int_0^{3/\sqrt2}\left((4+e^{xy}+9x)\,\vec\imath+(9+e^{xy}+4x)\,\vec\jmath+(e^{xy}+9x)\,\vec k\right)\cdot(\vec\imath-\vec k)\,\mathrm dx\,\mathrm dy

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3 0
3 years ago
Analyze the diagram below and complete the instructions that follow.
Flura [38]
This is an isosceles triangle, so both legs are of length 5√2.

Use the Pyth. Thm. to find the length of the hypotenuse.  Square 5√2 and double the result:  25(2) = 50; twice 50 is 100.  The square of the length of the hyp. is 100, and so the length of the hyp is sqrt(100), or 10 (answer).
4 0
3 years ago
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