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3 years ago

Write the expression as a single natural logarithm.3 ln x – 5 ln c

1 answer:

4 0

The rules are ...
$\Longrightarrow \ln(\frac{a}{b})=\ln(a)-\ln(b)$
$\Longrightarrow \ln(a^{b})=b\ln(a)$

Your expression makes use of both these rules.
$3\ln(x)-5\ln(c)=\ln(x^{3})-\ln(c^{5})=\ln \left( \dfrac{x^{3}}{c^{5}} \right)$

Your single logarithm is ...
$\ln \left( \dfrac{x^{3}}{c^{5}} \right)$

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True or false? The quadratic equation 10p2 - 5p = -8 has one solution.

pav-90 [236]

Answer: False

=============================================

Explanation:

I'll use x in place of p.

The original equation 10x^2-5x = -8 becomes 10x^2-5x+8 = 0 after moving everything to one side.

Compare this to ax^2+bx+c = 0

We have

a = 10
b = -5
c = 8

Plug those three values into the discriminant formula below

d = b^2 - 4ac

d = (-5)^2 - 4(10)(8)

d = 25 - 40*8

d = 25 - 320

d = -295

The discriminant is negative, which means we have no real solutions. If your teacher has covered complex or imaginary numbers, then you would say that the quadratic has 2 complex roots. If your teacher hasn't covered this topic yet, then you'd simply say "no real solutions".

Either way, this quadratic doesn't have exactly one solution. That only occurs when d = 0. Therefore, the original statement is false.

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2 years ago

At her job, Jesse. Earn 9 dollars and 50 cents per hour, she also earns a 60 dollar bonus every month. Jesse needs to earn at le

vichka [17]

Answer:

Jesse needs to work 43 hours in the month to make $400 and $60

work for answer: 9.50 x 43 = 408.5

example why it can't be lower or higher than 43 hours 9.50 x 42 = 399 or 9.50 x 44 = 418

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3 years ago

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Why cant i see the answer i cant fot brainly i dont have money like that

liraira [26]

Answer:

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Step-by-step explanation:

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0.4 greater or less than 0.41

marshall27 [118]

0.4 is exactly 0.01 less than 0.41 .

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3 years ago

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A survey of 35 people was conducted to compare their self-reported height to their actual height. The difference between reporte

Over [174]

Answer:

The test statistic is t = 3.36.

Step-by-step explanation:

You're testing the claim that the mean difference is greater than 0.7.

At the null hypothesis, we test if the mean difference is of 0.7 or less, that is:

$H_0: \mu \leq 0.7$

At the alternate hypothesis, we test if the mean difference is greater than 0.7, that is:

$H_1: \mu > 0.7$

The test statistic is:

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.