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Mars2501 [29]
3 years ago
5

WILL GIVE BRAINLIEST!!! How many terms are in the geometric sequence having a first term of 2, a last term of 32, and a common r

atio of -2?
Mathematics
1 answer:
Elza [17]3 years ago
7 0

Answer:

3

Step-by-step explanation:

first term a= 2

last term tn= 32

common ratio r= -2

number of terms

= tn=ar^n-1

32 = 2*(-2)^n-1

divide both sides by 2

32/2 = 2*(-2)^n-1/2

16 = (-2)^n-1

Then...use 16 in the power of 2

(-2)^4 = (-2)^n-1

The bases (-2), cancels out

so we have: 4 = n-1

collect like terms

4-1 = n

3 = n

n= 3

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Simplify using distributive property 4(z+2)+2(3-z)
riadik2000 [5.3K]

Answer:

2z+14

Step-by-step explanation:

you multiply

4*z   =4z

4*2   =8

and then you multiply

2*3=6

2*-z=-2z

the answer is 2z+14

5 0
2 years ago
six men completed a task in 24 hours and 48 minutes. how long would it take four men to complete the same task
Komok [63]

Answer:

37 hours and 12 minutes

Step-by-step explanation:

six men completed a task in 24 hours and 48 minutes which means (24 x 60) + 48 = 1488 minutes

x is the number of minutes it would take 4 men to complete

6(1488) = 4x

8928 = 4x

x = 2232

x = 2220 + 12 or 37 hours and 12 minutes

8 0
2 years ago
Write an equation of the hyperbola given that the center is at (2, -3), the vertices are at (2, 3) and (2, - 9), and the foci ar
zavuch27 [327]
Check the picture below.

so, the hyperbola looks like so, clearly a = 6 from the traverse axis, and the "c" distance from the center to a focus has to be from -3±c, as aforementioned above, the tell-tale is that part, therefore, we can see that c = 2√(10).

because the hyperbola opens vertically, the fraction with the positive sign will be the one with the "y" in it, like you see it in the picture, so without further adieu,

\bf \textit{hyperbolas, vertical traverse axis }
\\\\
\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1
\qquad 
\begin{cases}
center\ ( h, k)\\
vertices\ ( h,  k\pm a)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{ a ^2 + b ^2}\\
asymptotes\quad  y= k\pm \cfrac{a}{b}(x- h)
\end{cases}\\\\
-------------------------------

\bf \begin{cases}
h=2\\
k=-3\\
a=6\\
c=2\sqrt{10}
\end{cases}\implies \cfrac{[y- (-3)]^2}{ 6^2}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
c^2=a^2+b^2\implies (2\sqrt{10})^2=6^2+b^2\implies 2^2(\sqrt{10})^2=36+b^2
\\\\\\
4(10)=36+b^2\implies 40=36+b^2\implies 4=b^2
\\\\\\
\sqrt{4}=b\implies 2=b\\\\
-------------------------------\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 2^2}=1\implies \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 4}=1

3 0
3 years ago
The diameter of a cylindrical construction pipe is 4ft If the pipe is 17ft long, what is its volume? Use the value 3.14 for /pi,
Leya [2.2K]

Answer:

213.52 cubic ft

Step-by-step explanation:

Diameter of pipe = 4ft

radius for circle is half of diameter

thus radius of pipe = 1/2 of 4ft = 2 ft

length of pipe = 17 feet

volume of cylinder is given by \pi r^2l

where r is the radius and l is the length of cylinder

.

thus volume of pipe is calculated below using above values

volume \ of \ pipe = \pi r^2l\\volume \ of \ pipe = \3.14* 2^2*17 \\volume \ of \ pipe =  213.52

volume of pipe is 213.52 cubic ft.

5 0
3 years ago
How many pints are in 15 gallons
lesya692 [45]
There 60 pints in 15 gallon
6 0
3 years ago
Read 2 more answers
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