1) x = - 4, y = - 12; (- 4, - 12)
2) x = 34, y = 17; (34, 17)
3) x = 16, y = 7; (16, 7)
4) x = 7, y = - 4; (7, - 4)
5) x = - 4, y = 10; (- 4, 10)
6) x = 12, y = - 7; (12, - 7)
7) x = 5, y = 10; (5, 10)
8) x = 11, y = - 12; (11, - 12)
Answer:
-5/2+-1/2√37≤x≤-5/2+1/2√37
Step-by-step explanation:
Step 1: Find the critical points
-x^2-5x+3=0
For this equation: a=-1, b=-5, c=3
−1x^2+−5x+3=0
x=−b±√b2−4ac/2a
x=−(−5)±√(−5)2−4(−1)(3)/2(-1)
x=5±√37
/−2
x=-5/2+1/2√37
Step 2: Check intervals in between critical points
x≤-5/2+1/2 √37 (Doesn't work in original inequality)
-5/2+-1/2√37≤x≤-5/2+1/2√37 (Works in original inequality)
x≥-5/2+1/2 √37 (Doesn't work in original inequality)
5=1/2v-3
5=1/2v
+3 +3
8=1/2v
/1/2 /1/2
16=v
Answer:
A: 6, 12, 18, 24, 30
10, 20, 30, 40
B: 30
C: 5/6= 25/30 and 7/10= 21/30
D: 25/30>21/30 so 5/6>7/10
Answer:
Every fifth rose in each row of roses
Step-by-step explanation:
