(f+g)(x)=f(x)+g(x)
(f+g)(x)=3x+4+8x+1
(f+g)(x)=11x+5
(f+g)(0)=11(0)+5
(f+g)(0)=0+5
(f+g)(0)=5
The answer is 6 but idk that last part
Multiply the first equation by 7 and the second equation by 2, and then add.
Step-by-step explanation:
2f - 5g=-9
-7f + 3g=4
To eliminate any variable , we need to make the coefficients same with different sign and add it
the coefficient of 'f' in first equation is 2
the coefficient of 'f' in second equation is -7
We already have different sign so we make the coefficients same
To make the coefficient same , we multiply the first equation by 7 and second equation by 2
So equation becomes
14f - 35g = -63
-14f + 6g = 8
Now when we add both equations, 'f' gets cancelled
-29g = -55
Answer:
Therefore the value of 'y' is,
Step-by-step explanation:
Given:
To Find:
y= ?
Solution:
........Given
Step 1. Adding 50 to both the side we get
Step 2. Dividing by 10 on both the side we get
Therefore the value of 'y' is,
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