Answer:
Comprehensive deductible
Step-by-step explanation:
There is nothing called Premium deductible rather deductible determines how higher of lower a premium on a subject matter of insurance can be. Deductible is the amount with the insured have to bear at loss and any excess above the loss will be compensated by the insurance company.
Comprehensive deductible is the application to only to comprehensive insurance which was what Chad had on his motor vehicle. Comprehensive insurance covers majority of peril that happens to the insured vehicle. Therefore, comprehensive deductible is the deductible Chad has to bear himself before the insurance company take other losses upon theirself..
If he had $500 deductible on his car and total repair cost $700, then he will bear the $500 while the insurance company is entitled to pay only $200 as per policy statement.
since LM=LN there values are same which is given as 5.5 cm and MN =7cm
now draw a line LM which is 5.5 cm long. From one point of this line construct an arc 5.5 cm in upward direction.Then from the opposite end of the same line LM construct an arc 7 cm long in upward direction. Let it meet the the first arc at any point. The arcs will meet for sure at any angle. Join the two ends of line LN to this point where they meet. We get a triangle!
Remember to mark LM , LN and MN as soon as u draw them so as to avoid confusion.
<em>IF U WANT I'LL DO IT AND SEND A PHOTO</em>
A reflection is a transformation across a line called the line of reflection, so that the line of reflection is the perpendicular bisector of each segment joining each point and its image. ... A translation is an isometry , so the image of a translated figure is congruent to the preimage.
A. C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.
B. P(13,10)= 13! =13! =13·12·11·10·9·8·7·6·5·4.
(13−10)! 3!
C. f there is exactly one woman chosen, this is possible in C(10, 9)C(3, 1) =
10! 3!
9!1! 1!2!
10! 3!
8!2! 2!1!
10! 3!
7!3! 3!0!
= 10 · 3 = 30 ways; two women chosen — in C(10,8)C(3,2) =
= 45·3 = 135 ways; three women chosen — in C(10, 7)C(3, 3) =
= 10·9·8 ·1 = 120 ways. Altogether there are 30+135+120 = 285
1·2·3
<span>possible choices.</span><span>
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