(((x + y) / 3) + (1 / x)) / (5 + (15 / x))
The best way is to make it one fraction.
Multiply by ((3x/3x) / (3x/3x)) to remove the other fractions.
((x(x + y)) + 3(1)) / (5(3x) + 3(15))
(x^2 + xy + 3) / (15x + 45)
Then factor to simplify
(x^2 + xy + 3) / (3(x + 15))
Odd integers are 2 apart
they are n, n+2, n+4
the sum is 75
n+n+2+n+4=75
3n+6=75
minus 6 both sides
3n=69
divide both sides by 3
n=23
n+2=25
n+4=27
the integers are 23,25,27
Answers: The page numbers are 11 and 12
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Explanation:
Consecutive integers are ones that follow immediately after another. For example, the set {7,8,9,10} are consecutive.
Let,
- x = first page, some positive whole number
- x+1 = second page, follows immediately after page x
Adding those two said pages will lead to 23
first + second = 23
(x) + (x+1) = 23
2x+1 = 23
2x = 23-1
2x = 22
x = 22/2
x = 11 is the first page
x+1 = 11+1 = 12 is the second page
Check: 11+12 = 23 which confirms the answers.
