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2 years ago

What is the difference between a dependent and an independent variable?

Mathematics

1 answer:

Evgen [1.6K]2 years ago

8 0

Answer:

An independent variable is changed or controlled in an experiment, while a dependent variable is being tested and measured.

love your profile pic btw!

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Jasmine bought 32 kiwi fruit for $16. IfJasmine has $4, how many kiwi can shebuy?

Sav [38]

Answer:

8 kiwis

Step-by-step explanation:

(÷4)32=$16(÷4)

8 =$4

hope this helps

7 0

2 years ago

Help me pls don’t put random

Vladimir [108]

I think it’s A
Sorry if I’m wrong

4 0

2 years ago

Read 2 more answers

Which is most needed in order for groupwork technology to succeed?

ki77a [65]

The answer is D. An agreement from everyone on the collaborative team to share equally in the work load.

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2 years ago

The lassos high school senior class raised funds for an end of the year cruise getaway. The city gave them a special package for

kirill115 [55]

Answer:

Step-by-step explanation:

x = total number of students

1500 + 367x = 16,600

367x = 16,600 - 1500

367x = 15100

x = 15100 / 367

x = 41.14.......rounds to 41 students <==

this only works if the port fees and taxes that the city gave them are included in the money the class raised

5 0

2 years ago

B. Determine the values of a and b so that f is continuous.<br><br> Please help!

wlad13 [49]

Answer:

following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

$\lim_{x\to 2}+f(x) = \lim_{x\to 2}+ (ax^2-bx+3) = 4a-2b+3\\\\ \to 4a-2b+3 = 4\\\\ \therefore \ \ 4a-2b = 1\\\\$

The one-sided limits of F(x) at x = 3 must be equivalent for f(x) to be continuous at x = 3.

$\to \lim_{x\to 3}- f(x) = \lim_{x\to 3}- (ax^2-bx+3) = 9a-3b+3\\\\ \to \lim_{x\to 3}+ f(x) = \lim_{x\to 3}+ (2x-a+b) = 6-a+b\\\\$

So,

$\to 9a-3b+3 = 6-a+b\\\\\therefore\\ \to 10a -4b = 3$

$\to 4a - 2b = 1......(a)\\\to 10a - 4b = 3.......(b)\\$

In equation a multiply the by -2 and then add in the equation b:

$\to -8a + 4b = -2\\\to 10a - 4b = 3\\ \to 2a = 1\\\\ \to a = \frac{1}{2}\\\\ \to \ 4(\frac{1}{2}) - 2b = 1\\\\ \to 2 - 2b = 1\\\\ \to -2b = -1\\\\ \to b = \frac{1}{2}$

So, the value of $a \ and \ b= \frac{1}{2}$

4 0

2 years ago