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Crazy boy [7]
3 years ago
12

Tina is finding the quotient of. Is she correct? If not, what changes should be made?

Mathematics
1 answer:
Mice21 [21]3 years ago
5 0

For this case, we must find the quotient of

(15x ^ 3 + 12x ^ 2-9x) divided by3x, to verify if Tina was correct.

So:

\frac {15x ^ 3 + 12x ^ 2-9x} {3x} =\\\frac {15x ^ 3} {3x} + \frac {12x ^ 2} {3x} - \frac {9x} {3x} =\\5x ^ 2 + 4x-3

So, Tina was wrong, she had to divide by 3x.

Answer:

Option B


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2. Which of the following are terms of the series with nth term T-3n +17? a) 80 b) 170 c)217 d) 312 e) 278 f) 3566
pishuonlain [190]

Answer:

The correct options are a,b,e and f.

Step-by-step explanation:

It is given that the nth terms of the series is defined as

T_n=3n+17

Subtract 17 from both the sides.

T_n-17=3n

Divide both sides by 3.

\frac{T_n-17}{3}=n

The term Tₙ is a term of given series if n is a positive integer.

(a) The given term is 80.

n=\frac{80-17}{3}=21

Since n is a positive integer, therefore 80 is a term of given series.

(b) The given term is 170.

n=\frac{170-17}{3}=51

Since n is a positive integer, therefore 170 is a term of given series.

(c) The given term is 217.

n=\frac{217-17}{3}=66.67

Since n is not a positive integer, therefore 217 is a term of given series.

(d) The given term is 312.

n=\frac{312-17}{3}=98.33

Since n is not a positive integer, therefore 312 is a term of given series.

(e) The given term is 278.

n=\frac{278-17}{3}=87

Since n is a positive integer, therefore 278 is a term of given series.

(f) The given term is 3566.

n=\frac{3566-17}{3}=1183

Since n is a positive integer, therefore 3566 is a term of given series.

Thus, the correct options are a, b, e and f.

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I need help please!!
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Answer:

20

Step-by-step explanation:

6×2=12 + 8 = 20

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To the nearest tenth of a percent, what is 3/11 written as a percent?
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