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3 years ago

The surface area of a rectangular prism is increased by a factor of 16.

Mathematics

2 answers:

erik [133]3 years ago

7 0

The answer is 4 I think

d1i1m1o1n [39]3 years ago

3 0

Answer:

Step-by-step explanation:

The object is rectangular so it has 4 sides... 16/4=4

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Last Week Kellie ran 28 miles. This week she ran 32 miles. What was the percent change in the number of miles she ran? Please ex

Archy [21]

4/28= 1/7 = 14.3%...............

6 0

3 years ago

Read 2 more answers

Complete the proof. Prove: △VWX ≅ △XYV A) AAS B) ASA C) HL D) SAS

soldier1979 [14.2K]

Answer:

D) SAS

Step-by-step explanation:

Given:

Segment XY = segment VW

Segment XY ║ segment VW

∠ VXY = ∠ WVX (Alternate Interior angle Theorem)

Segment VX ≅ segment VX (relative property of Congruence)

Solution:

In △VWX and △XYV

Segment VX ≅ segment VX

∠ WVX = ∠ VXY

Segment XY = segment VW

∴ By Side Angle Side Congruence Property

△VWX ≅ △XYV by SAS

8 0

3 years ago

Read 2 more answers

A cable weighing 0.6 pounds per foot is attached to a small 80-pound robot, and then the robot is lowered into a 60-foot deep we

ollegr [7]

Answer:6060 foot-pounds

Step-by-step explanation:

Given

Weight of cable(w')=0.6 pound per foot

depth of well=60 foot

weight of wrench=7 Pound

Now work done in raising monkey with wrench $=w\cdot h$

$W_1=(80+7)\cdot 60=5220$ foot-pounds

Now work done in raising rope

robot rises by climbing up the cable with one end of the cable still attached thus robot support half the weight of cable so work done

$W_2==\int_{0}^{60}\frac{w'}{2}xdx$

$W_2=0.3\times 0.5\times (x^2)_0^{60}$

$W_2=540$ foot-pounds

$W_{net}=5220+540=6060$ foot-pounds

5 0

3 years ago

A:Write (⅔)² in expanded form, B. And then evaluate.

KatRina [158]

Answer:

4/9

Step-by-step explanation:

(2/3)^2

(2/3) x (2/3)

2 x 2 is 4

3 x 3 is 9

4/9

4 0

3 years ago

Do the three points lie on one line?

padilas [110]

Answer:

Yes. No graph paper.

Step-by-step explanation:

Let's say the 3 points are A, B, C.

If A, B and C lie on one line then $m_{AB} = m_{BC} = m_{AC}$

$m_{AB} = \frac{y_{B}-y_{A} }{x_{B}-x_{A}} = \frac{2-6}{3-5} = \frac{-4}{-2} = 2\\m_{BC} = \frac{y_{C}-y_{B} }{x_{C}-x_{B}} = \frac{8-2}{6-3} = \frac{6}{3} = 2\\\\m_{AC} = \frac{y_{C}-y_{A} }{x_{C}-x_{A}} = \frac{8-6}{6-5} = \frac{2}{1} = 2\\\\$

Hence, they lie on one line.

You don't need to use a graph paper to prove it.

4 0

2 years ago