<span>
D. Pyramid
...........
</span>
Answer:
km
Step-by-step explanation:
The submarine's path from its base forms a right triangle when its final position is "connected" to the base. We know that the right triangle has legs of
km and
km, and we need to find the length of its hypotenuse. To do so, we can use the Pythagorean Theorem, which states that in a right triangle,
, where
and
are the lengths of the triangle's legs and
is the length of the triangle's hypotenuse. In this case, we know what
and
are, and we need to solve for c, so after substituting the given values of
and
into
to solve for c, we get:

(Substitute
and
into the equation)
(Evaluate the squares on the LHS)
(Simplify the LHS)
(Symmetric Property of Equality)
(Take the square root of both sides of the equation)
(Simplify)
is an extraneous solution because you can't have negative distance, if that makes sense, so therefore, the submarine is approximately
km away from its base. Hope this helps!
Answer:
3.627 = d
Step-by-step explanation:
C = 11.4mm
d = ?
C = πd
11.4 = 22/7 × d
cross multiply
11.4 ×7 = 22d
79.8 = 22d
Divide both sides of the equation b 22
79.8/22 = 22d/22
3.627 = d
<em>Greetings from Brasil...</em>
In a trigonometric function
F(X) = ±UD ± A.COS(Px + LR)
UD - move the graph to Up or Down (+ = up | - = down)
A - amplitude
P - period (period = 2π/P)
LR - move the graph to Left or Right (+ = left | - = right)
So:
A) F(X) = COS(X + 1)
standard cosine graph with 1 unit shift to the left
B) F(X) = COS(X) - 1 = -1 + COS(X)
standard cosine graph with 1 unit down
C) F(X) = COS(X - 1)
standard cosine graph with shift 1 unit to the right
D) F(X) = SEN(X - 1)
standard Sine graph with shift 1 unit to the right
Observing the graph we notice the sine function shifted 1 unit to the right, then
<h3>Option D</h3>
<em>(cosine star the curve in X and Y = zero. sine start the curve in Y = 1)</em>
Not to seem rude, but you might have better luck in Business. Unless someone here know accounting lol