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Dennis_Churaev [7]
3 years ago
5

How many roots of f(x) are rational numbers? 1 2 4 6

Mathematics
1 answer:
wariber [46]3 years ago
4 0
I think it would be 2
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4b - 5 + (-a-3) i = 7 * 8i
Rudik [331]

Answer:

Simplifying

4b + -5 + (-1a + -3) * i = 7 + -8i

Reorder the terms:

4b + -5 + (-3 + -1a) * i = 7 + -8i

Reorder the terms for easier multiplication:

4b + -5 + i(-3 + -1a) = 7 + -8i

4b + -5 + (-3 * i + -1a * i) = 7 + -8i

Reorder the terms:

4b + -5 + (-1ai + -3i) = 7 + -8i

4b + -5 + (-1ai + -3i) = 7 + -8i

Reorder the terms:

-5 + -1ai + 4b + -3i = 7 + -8i

Solving

-5 + -1ai + 4b + -3i = 7 + -8i

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '5' to each side of the equation.

-5 + -1ai + 4b + 5 + -3i = 7 + 5 + -8i

Reorder the terms:

-5 + 5 + -1ai + 4b + -3i = 7 + 5 + -8i

Combine like terms: -5 + 5 = 0

0 + -1ai + 4b + -3i = 7 + 5 + -8i

-1ai + 4b + -3i = 7 + 5 + -8i

Combine like terms: 7 + 5 = 12

-1ai + 4b + -3i = 12 + -8i

Add '-4b' to each side of the equation.

-1ai + 4b + -4b + -3i = 12 + -4b + -8i

Combine like terms: 4b + -4b = 0

-1ai + 0 + -3i = 12 + -4b + -8i

-1ai + -3i = 12 + -4b + -8i

Add '3i' to each side of the equation.

-1ai + -3i + 3i = 12 + -4b + -8i + 3i

Combine like terms: -3i + 3i = 0

-1ai + 0 = 12 + -4b + -8i + 3i

-1ai = 12 + -4b + -8i + 3i

Combine like terms: -8i + 3i = -5i

-1ai = 12 + -4b + -5i

Divide each side by '-1i'.

a = -12i-1 + 4bi-1 + 5

Simplifying

a = -12i-1 + 4bi-1 + 5

Reorder the terms:

a = 5 + 4bi-1 + -12i-1

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