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Minchanka [31]
3 years ago
11

given the arithmetic sequence 3, 7, 11, 15, ..., what is a1, the first term? What is d, the common difference? Find the 151st te

rm of this sequence. What formula did you use? Be sure to show your work. Thank you.
Mathematics
1 answer:
JulijaS [17]3 years ago
5 0
It’s 12345678910 because the mathematical people said so.
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Pls help for brainliest
stealth61 [152]

Answer:

70cm2

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Step-by-step explanation:

8 0
3 years ago
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What is the sum of the first five terms of a geometric series with a1 = 6 and r = 1/3?
tresset_1 [31]
The sum of the terms of a geometric sequence with common ratio lesser than 1 is calculated through the equation,

                                  Sn = (a1) x (1 - r^n) / (1 - r)
Substituting the known values,
                                 S5 = (6) x (1 - (1/3)^5) / (1 - 1/3) = 242/27
Thus, the sum of the first five terms is approximately equal to 8.96. 

6 0
3 years ago
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Select all the expressions that are equivalent to (2)^n+³
eimsori [14]

Answer:

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

Step-by-step explanation:

Let us revise some rules of exponent

  • a^{m} × a^{m}  = a^{m+n}
  • (a^{m})^{n} = a^{m*n}

Now let us find the equivalent expressions of  (2)^{n+3}

A.

∵ 4 = 2 × 2

∴ 4 =  2^{2}

∴  (4)^{n+2} =  (2^{2})^{n+2}

- By using the second rule above multiply 2 and (n + 2)

∵ 2(n + 2) = 2n + 4

∴  (4)^{n+2} =  (2)^{2n+4}  

B.

∵ 4 = 2 × 2

∴ 4 =  2²

∴  4(2)^{n+1} = 2² ×  (2)^{n+1}

- By using the first rule rule add the exponents of 2

∵ 2 + n + 1 = n + 3

∴   4(2)^{n+1} =  (2)^{n+3}

C.

∵ 8 = 2 × 2 × 2

∴ 8 =  2³

∴  8(2)^{n} = 2³ ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 3 + n = n + 3

∴  8(2)^{n} =  (2)^{n+3}

D.

∵ 16 = 2 × 2 × 2 × 2

∴ 16 = 2^{4}

∴  16(2)^{n} = 2^{4}  ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 4 + n = n + 4

∴  16(2)^{n} =  (2)^{n+4}

E.

(2)^{2n+3} is in its simplest form

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

3 0
4 years ago
Which product is positive?<br> BA :)<br> OGO<br> (100)<br> G<br> 8<br> 3
romanna [79]
Wouldn’t the answer be 8 and 3
6 0
3 years ago
After drawing the line y = 2x − 1 and marking the point A = (−2, 7), Kendall is trying to decide which point on the line is clos
igor_vitrenko [27]

Answer:

Step-by-step explanation:

Having drawn the line, Kendall must verify that the point P belongs to the line y = 2x-1 and then calculate the distance between A-P  and verify if it is the closest to A or there is another one of the line

Having the point P(3,5) substitue x to verify y

y=2*(3)-1=6-1=5 (3,5)

Now if the angle formed by A and P is 90º it means that it is the closest point, otherwise that point must be found

d_{AP}=\sqrt{(y_{2}-y_{1})^{2}+(x_{2}-x_{1})^{2}}=\sqrt{(5-7)^{2}+(3-(-2}))^{2}}=\\\sqrt{(-2)^{2}+(5)^{2}}=\sqrt{29}

and we found the distance PQ and QA

; d_{PQ}=\sqrt{125}, d_{QA}=12

be the APQ triangle we must find <APQ through the cosine law (graph 2).

3 0
3 years ago
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