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3 years ago

Please help with this its simple

Mathematics

2 answers:

Tomtit [17]3 years ago

7 0

Answer:

324° is the correct answer

vagabundo [1.1K]3 years ago

6 0

Answer:

324

Step-by-step explanation:

(9 pi /5) * (180/pi)=324

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Juanita and Stephanie went to a clearance sale at a clothing store. Juanita bought 4 blouses and 3 skirts for a total of $ 72 .

Inessa05 [86]

4b+3s=72
6b+3s=96
Multiply the second equation by -1
-6b-3s=-96
Now you can cross out the +3s -3s
-2b=-24
Divide both sides by -2
b=12
s=8
So blouses cost $12 each and skirts cost $8 each

4 0

3 years ago

The temperature at sunrise was -3*F. By noon, the temperature climbed 18 degrees. By sundown the temperature was -14*F. How much

Nostrana [21]

Answer:

29*

Step-by-step explanation:

if th temperature was -3* and then climbed 18* it would end up being *15 because it was going up

but the it went down to -14* ,, which means that you have to get form 15* to -14*

you first go down 15* to get to 0 and go down *14 to get to -14*

when you add 15 and 14 it gets you to 29*

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4 years ago

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Natali [406]

Answer:

thx

Step-by-step explanation:

4 0

3 years ago

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Drag each equation and coordinate to the correct location on the table. Not all equations or coordinates will be used. In the ta

Elena L [17]

Answer:

Standard Form Equivalent Form Extreme Values

y=x^2-6x+17 (x-3)^2+8 (3,8)

y=x^2+8x+21 (x+4)^2+5 (-4,5)

y=x^2-16x+60 (x-8)^2-4 (8,-4)

Step-by-step explanation:

1) Standard form:

y=x^2-6x+17

Equivalent Form:

Can be found using completing the square method.

$y=x^2-6x+17\\y=x^2-2(x)(3)+(3)^2-(3)^2+17\\y=(x-3)^2-9+17\\y=(x-3)^2+8$

So, Equivalent form is: (x-3)^2+8

Extreme value:

Extreme values are basically the minimum and maximum value of the function.

Minimum Value will be found by finding derivative of the function:

The derivate is: 2x-6

Now, put the derivate equal to zero: 2x-6 = 0

$2x=6\\x=6/3 \\x=3$

Maximum value can be found by putting minimum value in the given function:

Put x = 3 and solve:

$(3)^2-6(3)+17\\9-18+17\\9-1\\=8\\$

So, the extreme values is: (3,8)

2) Standard form:

y=x^2+8x+21

Equivalent Form:

Can be found using completing the square method.

$y=x^2+8x+21\\y=x^2+2(x)(4)+(4)^2-(4)^2+21\\y=(x+4)^2-16+21\\y=(x+4)^2+5$

So, Equivalent form is: (x+4)^2+5

Extreme value:

Extreme values are basically the minimum and maximum value of the function.

Minimum Value will be found by finding derivative of the function:

The derivate of x^2+8x+21 is: 2x+8

Now, put the derivate equal to zero:

$2x+8 = 0\\2x=-8\\x=-8/2 \\x=-4$

So, minimum value is: -4

Maximum value can be found by putting minimum value in the given function:

Put x = -4 and solve:

$x^2+8x+21\\=(-4)^2+8(-4)+21\\=16-32+21\\=5$

So, Maximum value is: 5

So, the extreme values is: (-4,5)

3) Standard form:

y=x^2-16x+60

Equivalent Form:

Can be found using completing the square method.

$y=x^2-16x+60\\y=x^2-2(x)(8)+(8)^2-(8)^2+60\\y=(x-8)^2-64+60\\y=(x-8)^2-4$

So, Equivalent form is: (x-8)^2-4

Extreme value:

Extreme values are basically the minimum and maximum value of the function.

Minimum Value will be found by finding derivative of the function:

The derivate of x^2-16x+60 is: 2x-16

Now, put the derivate equal to zero:

$2x-16 = 0\\2x=16\\x=16/2 \\x=8$

So, minimum value is: 8

Maximum value can be found by putting minimum value in the given function:

Put x = 8 and solve:

$x^2-16x+60\\=(8)^2-16(8)+60\\=64-128+60\\=-4$

So, Maximum value is: -4

So, the extreme values is: (8,-4)

4 0

3 years ago

Read 2 more answers

The heights of students in a class are normally distributed with mean 55 inches and standard deviation 5 inches. Use the Empiric

maks197457 [2]

Answer: c)[50,60]

Step-by-step explanation:

The Empirical rule says that , About 68% of the population lies with the one standard deviation from the mean (For normally distribution).

We are given that , The heights of students in a class are normally distributed with mean 55 inches and standard deviation 5 inches.

Then by Empirical rule, about 68% of the heights of students lies between one standard deviation from mean.

i.e. about 68% of the heights of students lies between $\text{Mean}\pm\text{Standard deviation}$

i.e. about 68% of the heights of students lies between $55\pm5$

Here, $55\pm5=(55-5, 55+5)=(50,60)$

i.e. The required interval that contains the middle 68% of the heights. = [50,60]

Hence, the correct answer is c) (50,60)

4 0

3 years ago