Step-by-step explanation:
![\csc( - 450 \degree) \\ \\ = - \csc450 \degree \\ \\ = - \csc(360 \degree + 90\degree) \\ \\ = - \csc( 90\degree) \\ \\ = - 1](https://tex.z-dn.net/?f=%20%5Ccsc%28%20-%20450%20%5Cdegree%29%20%5C%5C%20%20%5C%5C%20%20%3D%20%20-%20%20%5Ccsc450%20%5Cdegree%20%5C%5C%20%20%5C%5C%20%20%3D%20%20-%20%20%5Ccsc%28360%20%5Cdegree%20%2B%2090%5Cdegree%29%20%5C%5C%20%20%5C%5C%20%20%3D%20-%20%20%5Ccsc%28%2090%5Cdegree%29%20%5C%5C%20%20%5C%5C%20%20%3D%20%20-%201)
I think this is the answer to your question And also the solution
<u>Answer </u><u>:</u>
In the given quadrilateral ABCD ,
- Angle BCA = 18°
- Angle ACD = 62°
Angle BCA = Angle CAD ( alternate interior angle )
Now in triangle CAD ,
We have two angles so by using angle sum property we can find the required third one ,
- Angle CAD + Angle ACD + Angle ADC = 180°
- 18 + 62 + Angle ADC = 180
- 80 + Angle ADC = 180
- Angle ADC = 180 - 80
- Angle ADC = 100
Answer:
0
Step-by-step explanation:
![40k = - 36](https://tex.z-dn.net/?f=40k%20%3D%20%20-%2036)
![k = - \frac{9}{10}](https://tex.z-dn.net/?f=k%20%3D%20%20-%20%20%5Cfrac%7B9%7D%7B10%7D%20)
![40( - \frac{9}{10} ) + 36 = 0](https://tex.z-dn.net/?f=40%28%20-%20%20%5Cfrac%7B9%7D%7B10%7D%20%29%20%2B%2036%20%3D%200)
![- 36 + 36 = 0](https://tex.z-dn.net/?f=%20-%2036%20%2B%2036%20%3D%200)