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shusha [124]
3 years ago
13

How many textbooks did rhonda sell

Mathematics
1 answer:
Gnom [1K]3 years ago
6 0

50

Step-by-step explanation:

She sold about 50 duhhh

she went to school to pick them up

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Which pair of numbers does 72 fall between
Svetach [21]
The pair of numbers that fall between 72 are 71 and 73.
4 0
3 years ago
Which two expressions are used to solve this problem?
kari74 [83]
Your first equation would be (97-25)/8
Then, your equation is 72/8
The answers are D and B!

Hope this helps!
4 0
4 years ago
Here are the records of two different sequences (A,B ) of a coin tossed eight times. A: T H H H H H H H B: H T T H T H H T If yo
ser-zykov [4K]

Answer: Sequence B is more probable than A.

Step-by-step explanation:

This two sequences are not equally probable. Sequence B is more probable than A due to the equal chances of getting head (H) and a tail (T). The probability of getting a head is equal to the probability of getting a tail which is 4/8 i.e 0.5

The sequence A is less probable because the head(H) occur more than tail (T). The probability of head occurring is almost a sure event i.e 1 which is not feasible.

6 0
4 years ago
Select the correct answer.
Evgesh-ka [11]

Answer:

B) 5(-3) either way its telling you to multiply 5 by -3

5 0
3 years ago
For the school play, the advance tickets cost 3, while tickets at the door cost 5. Thirty more tickets were sold at door than in
seropon [69]

Answer:

Number of tickets sold in advance = 310

Number of tickets sold  at the door = 340

Step-by-step explanation:

Note: This question is not complete. The complete question is therefore provided before answering the question as follows:

For the school play, the advance tickets cost $3, while tickets at the door cost $5. Thirty more tickets were sold at the door than in advance, and $2630 was collected. How many of each kind of ticket were sold?

The explation of the answer is now given as follows:

Let a represents number of tickets sold in advance. Therefore, we have:

a = number of tickets sold in advance at $3 each

a + 30 = number of tickets sold  at the door at $5 each

The total amount collected can be represented by this equation:

3a + 5(a + 30) = 2630

Solving for a, wee have:

3a + 5a + 150 = 2630

8a = 2630 - 150

8a = 2,480

a = 2,480 / 8

a = 310

Therefore, this implies:

Number of tickets sold in advance = 310

Number of tickets sold  at the door = a + 30 = 310 + 30 = 340

3 0
3 years ago
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