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3 years ago

What is the slope of the line? Please explain your answer.

Mathematics

2 answers:

Masteriza [31]3 years ago

3 0

The answer is D

At first glance we can see the slope of the line is negative. Automatically A and C are incorrect. Slope is y/x, we go 1 space down and 5 spaces to the right. (Run over rise)

Lyrx [107]3 years ago

3 0

Answer: D

Step-by-step explanation: Assuming the left point is A at (-2,2) and the right point is B at (3,1) we can determine the slope by using the “Rise over Run” rule where the change in Y is the “Rise” and the change in X is the “Run”. By setting up the equation y2-y1/x2-x1 we can plug in the coordinates from the variables and get 1-2/3+2 which leaves us with our answer m= -1/5

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3 years ago

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PLEASE HELP!! URGENT!!!! UNIT TEST!!!!

slavikrds [6]

ANSWER

$y=-\frac{4}{3}x+\frac{16}{3}$

$3y+4x=16$

EXPLANATION

Let us find the gradient of the line:

$-3x+4y=4$ by rewriting it in the slope intercept form.

$\Rightarrow 4y=3x+4$

We divide through by 4 now;

$\Rightarrow y=\frac{3}{4}x+1$

This is now in the form;

$y=mx+c$

where

$m=\frac{3}{4}$ is he slope.

This implies that the slope of the line that is perpendicular to this line will be the negative reciprocal of $m=\frac{3}{4}$ .

Thus the perpendicular line has slope,

$m=\frac{-1}{\frac{3}{4}}= -\frac{4}{3}$ .

Let the perpendicular line have equation,

$y=mx+c$

When we substitute the slope we have;

$y=-\frac{4}{3}x+c$

We substitute the point. $(4,0)$ to find c.

$0=-\frac{4}{3}(4)+c$

$0=-\frac{16}{3}+c$

$\frac{16}{3}=c$

We substitute c to obtain;

$y=-\frac{4}{3}x+\frac{16}{3}$

$3y+4x=16$

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3 years ago

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I don't know how to do this!!

saw5 [17]

3x-1=77 (due to exterior alternate angle)
Or, 3x=77-1
or, 3x=76
or, x=76/3
or, x=25.3

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2 years ago

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Step-by-step explanation:

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