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Morgarella [4.7K]

3 years ago

11

Which value for x makes the following equation TRUE? -2x - 4 = - 6

2 answers:

horrorfan [7]3 years ago

8 0

Answer:

1

Step-by-step explanation:

-2(1) = -2

then -2 - 4 = -6

-6 = -6

prisoha [69]3 years ago

3 0

Answer:

1

Step-by-step explanation:

Move all terms that don't contain x to the right side & solve.

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Trapezoid MNPQ is similar to Trapezoid RSTU. What is the length of the "x" on the misside side NP ? Also, what is the length of

ivolga24 [154]

Answer:

$x = 15$

$y = 25$

Step-by-step explanation:

Given

See attachment for MNPQ and RSTU

Required

Find x and y

To solve this question, we make use of equivalent ratios of corresponding side lengths.

The ratio of corresponding sides are:

$MN : RS$

$NP : ST$

$PQ : TU$

$MQ : RU$

From the attachment, we have:

$MN : RS \to 18 : 30$

$NP : ST \to x : 25$

$PQ : TU \to 15 : y$

To solve for x, we equate $MN : RS$ and $NP : ST$

$18 : 30 = x : 25$

Express as fraction

$\frac{18 }{ 30 }= \frac{x }{ 25}$

Make x the subject

$x = 25 * \frac{18 }{ 30 }$

$x = \frac{25 * 18 }{ 30 }$

$x = \frac{450}{ 30 }$

$x = 15$

To solve for y, we equate $MN : RS$ and $PQ : TU$

$18 : 30 = 15 : y$

Express as fraction

$\frac{18 }{ 30 }= \frac{15 }{ y}$

Make y the subject

$y = 15 * \frac{30 }{ 18 }$

$y = \frac{15 *30}{ 18 }$

$y = \frac{450}{ 18 }$

$y = 25$

8 0

3 years ago

A local health clinic surveys its patients about their waterdrinking habits. It found the data is normally distributed,the mean

satela [25.4K]

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

water drinking habits:

mean = 62 ounces

standard deviation = 5.2 ounces

Step 02:

normally distribution:

95% ===> 2 SD

(62 + 5.2 + 5.2) ounces = 72.4 ounces ==> + 2 SD

(62 - 5.2 - 5.2) ounces = 51.6 ounces ==> - 2 SD

The answer is:

51.6 ounces - 72.4 ounces

3 0

1 year ago

How do you solve the problem for this equation? 3+5x=3

Mazyrski [523]

Answer:

x=0

Step-by-step explanation:

3+5(0)=3

4 0

3 years ago

Read 2 more answers

Pls show full working out

sweet-ann [11.9K]

Answer:

Question 1a. i) $x=1.8m$

Question 1a. ii) $Volume=27.6m^3$

Question 1b) $Volume=65.9m^3$

Explanation:

<u><em>Question 1 a. i) Find the value of x.</em></u>

$tan(\theta )=\dfrac{opposite\text{ }leg}{adjacent\text{ }leg}$

For the smalll triangle you can write:

$tan(\theta )=\dfrac{x}{1m}$

For tthe big triangle:

$tan(\theta )=\dfrac{x+2.7m}{2.5m}$

Substitute:

$\dfrac{x}{1m}=\dfrac{x+2.7m}{2.5m}$

Solve for x:

$2.5x=x+2.7m\\\\2.5x-x=2.7m\\\\1.5x=2.7m\\\\x=2.7m/1.5\\\\x=1.8m$

<u><em>Question 1a ii) Find the volume of the frustrum</em></u>

Find the volume of a cone with height = 2.7m + 1.8m = 4.5m, and radius = 2.5m

Formula:

$Volume=(1/3)\pi \times radius^2\times height$

Substitute:

$Volume=(1/3)\pi \times (2.5m)^2\times 4.5m=9.375\pi m^3$

Find the volume of a cone with heigth = 1.8m and radius = 1m

$Volume=(1/3)\pi \times (1m)^2\times 1.8m=0.6\pi m^3$

Subtract the volume of the small cone from the volume of the big cone

$Volume\text{ }of\text{ }frustrum=9.375\pi m^3-0.6\pi m^3=8.775\pi m^3\approx 27.6m^3$

<u><em>Question 1b. Calculate the volume of the bin</em></u>

<u>i) Upper frustrum</u>

This is the same frustrum from the equation of above, thus ist volume is 27.6m³.

<u>ii) Lower frustrum</u>

$\dfrac{x}{2.0m}=\dfrac{x+2.4m}{2.5m}$

$2.5x=2(x+2.4m)\\\\2.5x=2x+4.8m\\\\0.5x=4.8m\\\\x=9.6m$

$Volume=(1/3)\pi \times (2.5m)^2\times (9.6m+2.4m)-(2.0m)^2\times (9.6m)$

$Volume=38.3m^3$

<u>iii) Add the volume of the two frustrums</u>

$Volume=27.6m^3+38.3m^3=65.9m^3$

6 0

3 years ago

Peter started to deposit 5000 philippine pesos quarterly in a fund that pays 1% compounded interest. How much will be in the fun

gayaneshka [121]

Answer:

1. Answer: F = P123,514.09

Step-by-step explanation:

1. Peter started to deposit P5,000 quarterly in a fund that pays 1% compounded quarterly. How much will be in

the fund after 6 years?

1. Answer: F = P123,514.09

8 0

3 years ago