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Vikki [24]
4 years ago
5

he given table shows the growth of Anytown, NC by providing the estimated population from 1970 to 2000. Year Population 1970 4,8

00 1980 6,300 1990 7,800 2000 9,300 Write an equation that represents the population in relation to years since 1970. Use x for the independent variable and y for the dependent variable. Write your answer in slope-intercept form. Do not use commas or spaces in your answer.
Mathematics
1 answer:
Morgarella [4.7K]4 years ago
4 0
The population is increasing by 1500 each year  and starts at 1970 population ( = 4800)  so the equation is
y=1500x+4800
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Solve 247 divided by 10(^2) . and 247x10 (^2)<br><br> what's different about the two answers?
guajiro [1.7K]
247 divided by 10^2 is 2.47 and 247 times 10^2 is 24,700

6 0
3 years ago
find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)
frutty [35]

Answer:

cosФ = \frac{1}{\sqrt{65}} , sinФ = -\frac{8}{\sqrt{65}} , tanФ = -8, secФ = \sqrt{65} , cscФ = -\frac{\sqrt{65}}{8} , cotФ = -\frac{1}{8}

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

  1. cosФ = \frac{x}{r}
  2. sinФ = \frac{y}{r}
  3. tanФ = \frac{y}{x}
  4. secФ = \frac{r}{x}
  5. cscФ = \frac{r}{y}
  6. cotФ = \frac{x}{y}
  • Where r = \sqrt{x^{2}+y^{2} } (the length of the terminal side from the origin to point (x, y)
  • You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = \sqrt{x^{2}+y^{2} }

∵ x = 1 and y = -8

∴ r = \sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = \frac{x}{r}

∴ cosФ = \frac{1}{\sqrt{65}}

∵ sinФ = \frac{y}{r}

∴ sinФ = -\frac{8}{\sqrt{65}}

∵ tanФ = \frac{y}{x}

∴ tanФ = -\frac{8}{1} = -8

∵ secФ = \frac{r}{x}

∴ secФ = \frac{\sqrt{65}}{1} = \sqrt{65}

∵ cscФ = \frac{r}{y}

∴ cscФ = -\frac{\sqrt{65}}{8}

∵ cotФ = \frac{x}{y}

∴ cotФ = -\frac{1}{8}    

8 0
3 years ago
50 POINTS PLEASE EXPLAIN ANSWER A slice is made perpendicular to the base of a right rectangular pyramid through the vertex.
Elza [17]
Um, we see that the slice created the triangle, and the formula to find the area of the triangle:
1/2×B×h where B represent Base and h represent height.
In this case, Base=5 cm
Height=11 cm
A=1/2×11×5
A=5.5×5
A=27.5 square cm. As a result, the area of the resulting two-dimensional cross section is 27.5 square cm. Hope it help!
8 0
3 years ago
Read 2 more answers
It’s just 2.a answer please
Inessa05 [86]
You have to convert the 30 inches into you know what and add them all together
8 0
3 years ago
I need help please help
Bogdan [553]
D.

you cannot have a negative amount of rainfall, so the predicted value of -32.4cm doesn't make sense.
8 0
3 years ago
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