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3 years ago

10

-10=2(-3x + 1)

1 answer:

Delicious77 [7]3 years ago

4 0

Ballance method is just a fance method of helping you remember to DO THE SAME THING TO BOTH SIDES OF AN EQUATION to keep it ballanced

-10=2(-3x+1)
divide BOTH SIDES by 2 to get rid of that 2 in front
-5=-3x+1
minus BOTH SIDES 1
-6=-3x
divide BOTH SIDES by -3
2=x

-x-7=-12
add7 BOTH SIDES
-x+7-7=-12+7
-x+0=-5
-x=-5
multiplY BOTH SIDES -1
x=5

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navik [9.2K]

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Anna11 [10]

Answer:

a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.

b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.

Step-by-step explanation:

I am going to solve this question treating these events as Venn probabilities.

I am going to say that:

Event A: Person has type A blood.

Event B: Person has Rh- factor.

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This means that $P(A) = 0.43$

15% of people have Rh- factor

This means that $P(B) = 0.15$

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This means that $P(A \cup B) = 0.52$

a. Find the probability that a person has both type O blood and the Rh- factor.

This is

$P(A \cap B) = P(A) + P(B) - P(A \cup B)$

With what we have

$P(A \cap B) = 0.43 + 0.15 - 0.52 = 0.06$

0.06 = 6% probability that a person has both type O blood and the Rh- factor.

b. Find the probability that a person does NOT have both type O blood and the Rh- factor.

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2 years ago

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slamgirl [31]

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Step-by-step explanation:

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3 years ago