28/11.2 = 2.5
since they are similar and openly stated as parrallelograms, you know that they have a scale of the longest edge of EFGH to the longest edge of JKLM
Answer:
18 chaperones
Step-by-step explanation:
1. How many times does 25 go into 225
2. Whatever that number is multiply it by two
3. That is how you get the number of chaperones
4. THE END
Hi there
-2 ≥ 4p + 6 + 4
-2 ≥ 4p + 10
4p +10 ≤ -2
Now subtract 10 form both sides
4p + 10 - 10 ≤ -2 - 10
4p ≤ -12
Divide by 4
4p/4 ≤ -12/4
p ≤ -3
I hope that's help:)
I think the answer is x>-28
