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Setler [38]
3 years ago
8

What is solution to this system of equations? x + 4y = 12 and x = 0PLSSS hurry​

Mathematics
2 answers:
Step2247 [10]3 years ago
7 0

Answer:

y = 3

Step-by-step explanation:

It is given that x = 0,

So by substituting it in the equation x + 4y = 12

=> 0 + 4y = 12

=> 4y = 12 - 0 (by transposing)

=> 4y = 12

=> y = 12/4 = 3

Hope you understood!!

Margaret [11]3 years ago
3 0

Answer:

x=0 and y=3

Step-by-step explanation:

If x=0, then we can just plug that value into the other equation and solve for y:

x+4y=12

0+4y=12

4y=12

y=3

Therefore, the solution to the system of equations is x=0 and y=3

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Points A and B have opposite x-coordinates but the same y-coordinates.
n200080 [17]

Answer:

c

Step-by-step explanation:

start before a and count until you get to B

5 0
3 years ago
A dump truck brought 1⁄3 of a ton of rock on the first trip, 1⁄2 of a ton on the second trip, but on the third trip, had to take
Allisa [31]

Answer:

1/30 of a ton

Step-by-step explanation:

Write this as an expression:

1/3 of a ton and 1/2 of a ton were taken to the site.

4/5 of a ton were remove from the site.

Amount of a ton at the site  =   \frac{1}{3}+ \frac{1}{2}- \frac{4}{5}

Solve the equation by finding <u>common denominators</u> (when the bottom numbers are the same).

(\frac{1}{3}+ \frac{1}{2})- \frac{4}{5}       Focus on the first part. The least common multiple (LCM) of 3 and 2 is "6", which will become the denominator.

For <u>1/3 to become ?/6</u>, multiply top and bottom by 2.

For <u>1/2 to become ?/6</u>, multiply top and bottom by 3.

(\frac{2}{6}+ \frac{3}{6})- \frac{4}{5}

Now we can add the numerators together over the same denominator.

\frac{5}{6}- \frac{4}{5}

Do the same thing as before and change the denominators. The LCM of 6 and 5 is "30".

For <u>5/6 to become ?/30</u>, multiply top and bottom by 5.

For <u>4/5 to become ?/30</u>, multiply top and bottom by 6.

\frac{25}{30}- \frac{24}{30}

Subtract the numerators:

\frac{1}{30}                  Answer in tons

Therefore there was 1/30 of a ton of rock left at the construction site.

7 0
3 years ago
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Arte-miy333 [17]

Answer:

In this problem, we need to describe the relation between variables, if that relation is functional or not. It's important to say that we assumed that the first variable is independent, and the second is dependent.

<h3>(a)</h3>

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<h3>(b)</h3>

Height - Age of the person: These relation is not functional, becasuse age can't be a dependent variable, beacuse the age of a person doesn't depends on his height.

<h3>(c)</h3>

Gasoline price - Day of the Month: These relation is not functional, becasue time must be the independent variable.

<h3>(d)</h3>

Day of the Month - Gasoline price: These realation make sense, beacuse the price of the gasoline can be depedent of the day of the month.

<h3>(e)</h3>

A number and its fifth part: Notice that the fifth part depends on the number, it's defined by it, so this can be a function.

<h3>(f)</h3>

A number and its square root: These two variables represent a function, where "a number" represents the domain value and "its square root" represents a range vale.

4 0
3 years ago
a file that is 278 megabytes is being downloaded. If downloaded is 14.1% complete, how many megabytes been downloaded? To round
Gekata [30.6K]
14.1% of 278 is 39.2. So 39.2 megabytes have been downloaded.
4 0
4 years ago
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Simplify this expression
Fantom [35]

Answer:

{3}^{ - 3}  =  ({ \frac{1}{3} )}^{3}  =  \frac{1}{27}

8 0
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