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2 years ago

What is solution to this system of equations? x + 4y = 12 and x = 0PLSSS hurry

Mathematics

2 answers:

Step2247 [10]2 years ago

7 0

Answer:

y = 3

Step-by-step explanation:

It is given that x = 0,

So by substituting it in the equation x + 4y = 12

=> 0 + 4y = 12

=> 4y = 12 - 0 (by transposing)

=> 4y = 12

=> y = 12/4 = 3

Hope you understood!!

Margaret [11]2 years ago

3 0

Answer:

x=0 and y=3

Step-by-step explanation:

If x=0, then we can just plug that value into the other equation and solve for y:

x+4y=12

0+4y=12

4y=12

y=3

Therefore, the solution to the system of equations is x=0 and y=3

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3 years ago

arlik [135]

Given:

In a right angle triangle θ is an acute angle and $\tan\theta =\dfrac{3}{5}$ .

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The value of $\cos \theta$ .

Solution:

In a right angle triangle,

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$\tan\theta =\dfrac{3}{5}$

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By using Pythagoras theorem,

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$\cos \theta=\dfrac{Base}{Hypotenuse}$

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Therefore, the value of $\cos \theta$ is $\dfrac{5}{\sqrt{34}}$ .

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2 years ago

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NNADVOKAT [17]

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3 years ago

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jasenka [17]

Answer:

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3 years ago

Find all integers $n$ for which $\frac{n^2+n+1}{n-1}$ is an integer.

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$\dfrac{n^2+n+1}{n-1}=\dfrac{(n-1)^2+3(n-1)+3}{n-1}=n-2+\dfrac3{n-1}$

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3 years ago

What is solution to this system of equations? x + 4y = 12 and x = 0PLSSS hurry​

What is solution to this system of equations? x + 4y = 12 and x = 0PLSSS hurry