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Lubov Fominskaja [6]

3 years ago

14

If the instructions for a problem ask you to use the smallest possible domain to completely graph two periods of y=5 + 3cos 2(x-

pi/3) what should you use for the x min and x max

1 answer:

katovenus [111]3 years ago

8 0

We need two periods so we need to cos go from 0 to 2π

x - pi/3 = 0

x = pi/3

x - pi/3 = 2pi

x = 2pi + pi/3

x = 7pi/3

xmin = pi/3

xmax = 7pi/3

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Which of the following describes the sequence 1,1,2,3,5

KIM [24]

Answer:

Step-by-step explanation:

It starts at 1 adds 1 which got you 2 , then 1 plus 2, is 3, then 2 plus 3 is 5, you get it?

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4 years ago

Which one of the following is a unit vector?

wariber [46]

C ljsijsosbsosjsoskdksbsjsbs

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3 years ago

I need help please. <br> Solve this plz for A.

kirill [66]

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3(- 6 + m)(- 4 + m)

Step-by-step explanation:

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5 0

3 years ago

Make x the subject! urgent help

Serhud [2]

Answer:

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Step-by-step explanation:

I supposed that is a "n".

Steps as below:

${t}^{2} = b - \frac{n}{x} \\ b - \frac{n}{x} = {t}^{2} \\ - \frac{n}{x} = {t}^{2} - b \\ \frac{n}{x} = - ( {t}^{2} - b) \\ \frac{n}{x} = b - {t}^{2} \\ n = x(b - {t}^{2} ) \\ x(b - {t}^{2} ) = n \\ x = \frac{n}{b - {t}^{2} }$

4 0

2 years ago

Read 2 more answers

xand y are light house. y being 20km due east of x and from a ship due south of x the bearing of y was 055°. what is the distanc

leonid [27]

Answer:

I) |xz| ≈ 28.6 km

II) |yz| ≈ 34.8 km

Step-by-step explanation:

Let's assume that the position of ship due south of x is z (aà pictor representation of the question is attached)

|xy| = 20 km, |xz| = ?, |yz| = ?, θ(y) = 55°

Using Trigonometric ratio - SOHCAHTOA

I) Tan θ = |xz| ÷ |xy| ⇒ Tan 55° = |xz| ÷ 20

|xz| = 20 * Tan 55 = 20 * 1.428

|xz| = 28.56 km

|xz| ≈ <u>28.6 km</u>

<u />

II) Cos θ = |xy| ÷ |yz| ⇒ Cos 55° = 20 ÷ |yz|

|yz| * Cos 55° = 20 ⇒ |yz| = 20 ÷ Cos 55°

|yz| = 20 ÷ 0.574 = 34.84 km

|yz| ≈ <u>34.8 km</u>

4 0

3 years ago