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3 years ago

12

Consider the system of equations.

2 answers:

Lyrx [107]3 years ago

6 0

Answer:

-2 and -3

Step-by-step explanation:

got it right on edg

skelet666 [1.2K]3 years ago

6 0

Answer:

The Answer is ( B) -2, (D)-3,

Step-by-step explanation:

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d1i1m1o1n [39]

This is a right triangle, so first find the distance between the two legs...

Points where the numbers are the same indicate a point that is on the same axis as the other

(-3, 3) and (-3, 2) have a distance of 1

(-3,2) and (1,2) have a distance of 4

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The area is 2

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2 years ago

What 18 time 178 plus 98-2

Sidana [21]

178 * 18 + (98-2)
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3 years ago

Read 2 more answers

Pedro fills a glass 2/4 full with orange juice write a fraction with a denominator of 6 that is greater than 2/4

Deffense [45]

A fraction with the denominator of 6 and is breather than 2/4 would be 5/6 or 4/6

8 0

2 years ago

· The angles of a pentagon are in the ratio<br>4:8 : 6 : 4 : 5. Find each angle of the<br>pentagon

SVEN [57.7K]

Answer:

540 degrees in a pentagon

4 + 8 + 6 + 4 + 5 = 27

540/27 = 20

4 X 20 = 80 degrees

8 X 20 = 160 degrees

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7 0

2 years ago

I need help with this question

Novay_Z [31]

Answer:

$\frac{\sqrt{3} - 1}{2\sqrt{2}}$

$\frac{-(\sqrt{3} + 1)}{2\sqrt{2}}$

$- \frac{\sqrt{3} - 1}{\sqrt{3} + 1}$

Step-by-step explanation:

Given $\frac{11 \pi}{12} = \frac{3 \pi}{4} + \frac{\pi}{6}$

(A) $sin(\frac{11\pi}{12}) = sin (\frac{3 \pi}{4} + \frac{\pi}{6})$

We know that Sin(A + B) = SinA cosB + cosAsinB

Substituting in the above formula we get:

$sin (\frac{3\pi}{4} + \frac{\pi}{6}) = \frac{1}{\sqrt{2}} . \frac{\sqrt{3}}{2} + \frac{-1}{\sqrt{2}}. \frac{1}{2}$

$$ \implies \frac{1}{\sqrt{2}} (\frac{\sqrt{3} - 1}{2}) = \frac{\sqrt{3} - 1}{2\sqrt{2}}$

(B) Cos(A + B) = CosAcosB - SinASinB

$cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6}})$

$\implies \frac{-1}{\sqrt{2}}. \frac{\sqrt{3}}{2} - \frac{1}{\sqrt{2}} . \frac{1}{2}$

$\implies cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6})$

$$ = \frac{-(\sqrt{3} + 1)}{2\sqrt{2}}$

(C) Tan(A + B) = $\frac{Sin(A +B)}{Cos(A + B)}$

From the above obtained values this can be calculated and the value is $- \frac{\sqrt{3} - 1}{\sqrt{3} + 1}$ .

3 0

2 years ago