Answer:
A
Step-by-step explanation:
The green is the starting place, when you move from a point on the green triangle to the blue one, you go 5 to the left and 3 down.
If you mean the price is now 120% of the original, $<span>4.74 (3.95 * 0.8) is the new price.
If you mean the price is now 80% of the original, $3.16 (3.95 * 1.2) is the new price.</span>
Answer:
Number of hot dogs sold = 56
Number of hamburgers sold = 52
Step-by-step explanation:
Let
Number of hot dogs sold = x
Number of hamburgers sold = y
We can make equation from given equations:
(Hot dogs were sold for $.50 (fifty cents), and hamburgers were sold for $1 (one dollar). The total money raised by your class was $80. )
(Together you sold 108 hot dogs and hamburgers.)
Now we cam solve these system of equations to find value of x and y

Subtract both equations to get value of x:

We get value of x = 56
Now putting value of x in equation 2 to find value of y

So, we get y = 52
Therefore,
Number of hot dogs sold = x = 56
Number of hamburgers sold = y = 52
Answer:
95% confidence interval for the difference between the average mass of eggs in small and large nest is between a lower limit of 0.81 and an upper limit of 2.39.
Step-by-step explanation:
Confidence interval is given by mean +/- margin of error (E)
Eggs from small nest
Sample size (n1) = 60
Mean = 37.2
Sample variance = 24.7
Eggs from large nest
Sample size (n2) = 159
Mean = 35.6
Sample variance = 39
Pooled variance = [(60-1)24.7 + (159-1)39] ÷ (60+159-2) = 7619.3 ÷ 217 = 35.11
Standard deviation = sqrt(pooled variance) = sqrt(35.11) = 5.93
Difference in mean = 37.2 - 35.6 = 1.6
Degree of freedom = n1+n2 - 2 = 60+159-2 = 217
Confidence level = 95%
Critical value (t) corresponding to 217 degrees of freedom and 95% confidence level is 1.97132
E = t×sd/√(n1+n2) = 1.97132×5.93/√219 = 0.79
Lower limit = mean - E = 1.6 - 0.79 = 0.81
Upper limit = mean + E = 1.6 + 0.79 = 2.39
95% confidence interval for the difference in average mass is (0.81, 2.39)
Tbe question doesn't state the number of days he walked to school out of 20 school days in the
Month of February.
Answer:
Kindly check explanation
Step-by-step explanation:
To. Obtain the fractional representayion for the number of days he walked to school ;
Let the number of days he walked to school = 10 (this is an hypothesized value)
Number of school days in February = 20
Fraction = 10 /20 = 0.5
The percentage of times walked to school : multiply the fraction obtained above by 100%
0.5 * 100% = 50%
Just put the desired value and proceed uSing the steps described above.