All categories

2 years ago

Please help me out :)

Mathematics

1 answer:

Vanyuwa [196]2 years ago

8 0

The angle between the legs labeled $x$ and $y$ is complementary to the angle with measure 31 degrees, so that angle has measure 90 - 31 = 59 degrees. Then

$\sin59^\circ=\dfrac{400}x\implies x=\dfrac{400}{\sin59^\circ}\approx466.7$

You might be interested in

Mariam’s uncle donate 120 cans of juice and 90 packs of cheese cracker for the school picnic. Each student must receive the same

monitta

Answer:

8 students,

15 cans of juice and 11 packs of cheese cracker

Step-by-step explanation:

Mariam’s uncle donate 120 cans of juice and 90 - 2 = 88 packs of cheese cracker (eats two packs) for the school picnic.

Factor these numbers:

$120=2\cdot 60=2\cdot 2\cdot 30=2\cdot 2\cdot 2\cdot15=2\cdot 2\cdot 2\cdot 3\cdot 5\\ \\88=2\cdot 44=2\cdot 2\cdot 22=2\cdot 2\cdot 2\cdot 11$

The greatest common factor is

$2\cdot 2\cdot 2=8,$

so the greatest number of students who can share the food equally is 8 and each student will get $3\cdot 5=15$ cans of juice and 11 packs of cheese cracker.

4 0

2 years ago

lone star supply company bought a computer system with a color monitor for 1,598 if the color monitor cost $699 how much did the

ladessa [460]

Answer: $899

Step-by-step explanation: I subtracted $699 from $1598 so it would look like this

$1598-$699=$899

5 0

2 years ago

You have drawn a simple random sample of 36 college students, asking each student how much rent they pay per month. You obtain a

Karo-lina-s [1.5K]

Answer:

$573-1.690\frac{22}{\sqrt{36}}=566.8033$

$573+1.690\frac{22}{\sqrt{36}}=579.1967$

And the 90% confidence interval would be between [566.80 and 579.20]

Step-by-step explanation:

Information given

$\bar X=573$ represent the sample mean

$\mu$ population mean (variable of interest)

s=22 represent the sample standard deviation

n=36 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

$df=n-1=36-1=35$

The Confidence level is 0.90 or 90%, the significance would be $\alpha=0.1$ and $\alpha/2 =0.05$ , and the critical value for this case would be $t_{\alpha/2}=1.690$