Answer:
The final charges of each sphere are: q_A = 3/8 Q
, q_B = 3/8 Q
, q_C = 3/4 Q
Explanation:
This problem asks for the final charge of each sphere, for this we must use that the charge is distributed evenly over a metal surface.
Let's start Sphere A makes contact with sphere B, whereby each one ends with half of the initial charge, at this point
q_A = Q / 2
q_B = Q / 2
Now sphere A touches sphere C, ending with half the charge
q_A = ½ (Q / 2) = ¼ Q
q_B = ¼ Q
Now the sphere A that has Q / 4 of the initial charge is put in contact with the sphere B that has Q / 2 of the initial charge, the total charge is the sum of the charge
q = Q / 4 + Q / 2 = ¾ Q
This is the charge distributed between the two spheres, sphere A is 3/8 Q and sphere B is 3/8 Q
q_A = 3/8 Q
q_B = 3/8 Q
The final charges of each sphere are:
q_A = 3/8 Q
q_B = 3/8 Q
q_C = 3/4 Q
Answer:
phenomenon is dry adiabatic lapse rate
Explanation:
air babble elevation = 1000 meters
temperature = 10 degree decrease
to find out
phenomenon is best described as
solution
we know bubble is unsaturated air is rising through the atmosphere
bubble reach height 1000 meter and temperature 10 degree
than phenomenon is dry adiabatic lapse rate
because when parcel of air is lift and pressure decrease with height and temperature fall down by expansion and rate of temperature fall 1°C /100 m in dry Adiabatic lapse rate parcel descends to higher pressure and temperature then increase at rate 1°C / 100 meters
this his phenomenon is dry adiabatic lapse rate
The 'plum pudding' model of the atom was proposed by JJ Thomson, who had also discovered the electron. It was put forth before the discovery of the nucleus. According to this model, the atom is a sphere of positive charge, and negatively charged electrons are embedded in it to balance the total positive charge
Formula for potential energy is:
pe = m * g * h
Where:
m = mass of an object
g = gravitational acceleration
h = height at which object is placed
From this equation we can make conclusion that increasing mass also increases potential energy. Object b has double the mass so it has double the potential energy.
Object a:
pe = m * 9.81 * 1
pe = 9.81 J
Object b:
pe = 2m * 9.81 * 1
pe = 19.62 J
It’s D. An enlargement (hope this helps!)